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1 answer
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Question regarding to the basis of L^p space via compact self adjoint operators. ( eg: inverse of -laplacian )

Do eigenfunctions of inverse of elliptic operator (eg: Laplacian) form basis of $L^P(\Omega)$ ? For p=2 we know the answer is yes, I am looking for p>2. More generally, is it true that eigenfunctions ...
user45267's user avatar
-2 votes
1 answer
3k views

Separability of continuous functions with compact support [closed]

Hi, is the space $C_0(\mathbb{R}^m)$, $m \in \mathbb{N}$ of continuous functions with compact support separable? If yes: where can I find a proof for that? Please note: this is not a duplicate of ...
fjodor_d's user avatar
-2 votes
2 answers
325 views

$f\in (W^{1,p}(\Omega)\cap C(\Omega) \cap L^{\infty}(\Omega))\setminus C(\bar{\Omega})$, $f=0$ on $\partial \Omega$ imply $f\in W^{1,p}_{0}(\Omega)$?

Q1: Let $p\geq 1$, and let $f\in W^{1,p}(\Omega)\cap C(\Omega)$. Assume also $f\in L^{\infty}(\Omega)$ and $f=0$ on $\partial \Omega$. Is it true that $f\in W^{1,p}_{0}(\Omega)$ even if $f\notin C(\...
Medo's user avatar
  • 852
-2 votes
1 answer
193 views

Analysis of Sobolev spaces [closed]

I just wanted to know wthether the following is OK or not. Let $X$ be $H_0^1(\Omega)\bigcap L^{\infty}(\Omega)$, thought of as a subspace of $H^1_0(\Omega)$ and endowed solely with the usual $H^1$ ...
Alexander's user avatar
  • 157

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