6
$\begingroup$

I was this past year working with a bright high-schooler on algebraic geometry following Reid's book Undergraduate Algebraic Geometry, and we got all the way to proving that there is at least one line on a non-singular cubic surface over an algebraically closed field that has a point whose tangent space intersects the original surface in a nodal plane cubic of type $y^2=x^3$ (I believe in char=3 there is another type of nodal plane cubic, which we didn't examine in detail). However, one fun thing is of course looking at examples over arbitrary fields where the lines are all defined over that base field.

There are well-known examples over the reals, but I was wondering about what happens over finite fields in low characteristic. In particular what is the "smallest", in the sense of the smallest field and the simplest surface, and "best", in the sense of the most symmetric while having all lines distinct over the base field, example. Ideally all the points of intersection are in a single affine chart, so one could make a toy model of the affine part of the (rational points on the) surface together with the (rational points on the) lines, in some combinatorially-pleasing embedding.

The stretch goal is to know what is the automorphism group of the configuration of 27 lines, in this particular small example.

$\endgroup$
4
  • $\begingroup$ In case it isn't obvious: I want a specific finite field, an explicit equation for the cubic surface, and an explicit description (in whatever way) for the lines. $\endgroup$
    – David Roberts
    Commented 4 hours ago
  • 2
    $\begingroup$ A cubic surface where all $27$ lines are defined over a finite field $\mathbb F_q$ has $q^2+7q +1$ points over $\mathbb F_q$. The embedding in $\mathbb P^3$ gives the inequality $q^2+7q +1 \leq q^3 + q^2+q+1$ which requires $q\geq \sqrt{6}$, so we must have $q$ at least $3$. $\endgroup$
    – Will Sawin
    Commented 3 hours ago
  • 2
    $\begingroup$ For the Fermat hypersurfaces in characteristic different from $2$ and $3,$ all twenty-seven lines are rational if the base field contains a primitive sixth root of unity. If the base field is $\mathbb{F}_q$, this is equivalent to the congruence $q\equiv\ 1\ (\text{mod}\ 6)$. So $q=7$ gives one example. $\endgroup$ Commented 3 hours ago
  • $\begingroup$ If you want all intersections of lines to be in one affine chart, then the intersections of the 27 lines with some plane should give 27 distinct points on a plane cubic over $\mathbf F_q$. I think this requires $q$ to be at least 13. $\endgroup$ Commented 47 mins ago

1 Answer 1

7
$\begingroup$

It is the Fermat cubic surface over $\mathbb{F}_4$ or (if you prefer $\mathbb{F}_p$) over $\mathbb{F}_7$.

There are quite a few papers on this topic. Firstly in [1] Swinnerton-Dyer showed (amongst other things) there is a smooth split cubic surface over $\mathbb{F}_q$ if and only if $q \neq 2,3,5$ (we say a cubic surface is split if all 27 lines are defined over the ground field).

The existence a smooth split cubic surface over $\mathbb{F}_4$, but not $\mathbb{F}_5$, is some funny combinatorial coincidence about the geometry of the projective plane over finite fields of even characteristic.

In characteristic 2 all kinds of funny things happen. For example over $\mathbb{F}_4$ the Fermat cubic surface has automorphism group $\mathrm{PSU}_4(\mathbb{F}_2)$, which is the largest possible automorphism group, see [2]. This surface is split over $\mathbb{F}_4$ hence is the required surface.

Over $\mathbb{F}_7$ it is also split and is known to have the largest possible automorphism group of all smooth cubic surfaces over an algebraically closed field of characteristic not equal to $3$ (again see [2]). But since there are 6th roots of unity in $\mathbb{F}_7$, all automorphisms are actually defined over $\mathbb{F}_7$.

[1] Swinnerton-Dyer, Peter, Cubic surfaces over finite fields. Math. Proc. Cambridge Philos. Soc. 149 (2010), no. 3, 385–388.

[2] Vikulova, Anastasia V. The most symmetric smooth cubic surface over a finite field of characteristic 2. Finite Fields Appl. 98 (2024), Paper No. 102470, 25 pp.

$\endgroup$
1
  • 1
    $\begingroup$ The thesis of Raymond Cheng studies generalizations of cubic Fermat surfaces in characteristic $2$ to “$q$-bic varieties.” These each have a large (unitary) group of automorphisms. $\endgroup$ Commented 2 hours ago

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .