Let $B_n$ denote the Bernoulli numbers and let $\phi=\frac{1+\sqrt{5}}2$ be the golden ratio.

I encountered the following infinite sum and would like to ask:

Question.Is this true? If so, any proof? $$\sum_{\pmb{k=0}}^{\infty}\sum_{j=k}^{2k}\binom{k}{j-k}\frac{B_{j+1}}{j+1} =\frac{2\,\log\phi}{1-2\phi}.$$

*Caveat.* Do not try reversing summations, it diverges!

**Update.** Thanks to Henri Cohen for observing the typo, the sum has been edited to start at $k=0$. Readers are advised that Nemo's answer is given when the sum begins with $k=1$.

knownBernoulli polyomial of odd degree that has "non-trivial" roots is $B_{11}(x)$, whose "non-trivial" roots are the golden ratio and its conjugate. $\endgroup$ – EFinat-S Jun 16 '17 at 16:57