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Let $f$ be a compactly supported function in $\Omega \subset \mathbb{R}^3$ and

$\Delta u=f$ in $\Omega$

such that $D^{\alpha}u=0$ on $\partial \Omega$ for every multi-index $\alpha$ with $|\alpha| \geq 0$. Is $f$ necessarily zero?

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No. Take any $u$ which is not zero, but compactly supported in $\Omega$. Then define $f=\Delta u$; it will be also compactly supported, and non-zero.

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