3
$\begingroup$

Let $\Omega$ be a bounded region in $\mathbb{R}^n$ and $a_1, a_2$ be smooth positive functions such that $a_1-a_2$ is compactly supported in $\Omega$, and $a_i>c>0$, for some constant $c$. Suppose there exists $\lambda>0$ and $u_i\in H^1_0(\Omega)$ such that

$$-a_i \Delta u_i=\lambda u_i,$$ and $\frac{\partial u_1}{\partial \nu}=\frac{\partial u_2}{\partial \nu}$ on $\partial \Omega$, where $\nu$ is the unit normal vector on $\partial \Omega$. Is $a_1=a_2$ in $\Omega$?

$\endgroup$

1 Answer 1

3
$\begingroup$

In general the answer is "no." Let $\Omega = (-\pi/2,\,\pi/2) \subset \mathbb{R}$, and for $\varphi \in C^{\infty}_0(\Omega)$ take $$u_1 = \cos(x), \quad u_2 = \cos(x) + \epsilon \varphi$$ $$a_1 = 1, \quad a_2 = \frac{\cos(x) + \epsilon \varphi}{\cos(x) - \epsilon \varphi''},$$ $$\lambda = 1.$$ For $\epsilon > 0$ small, the desired conditions are satisfied, but $a_1 \neq a_2$.

$\endgroup$
1
  • $\begingroup$ Thank you Connor. Do you think the above could also hold for more than one eigenvalue? $\endgroup$ Mar 21, 2019 at 14:26

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.