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Piotr Hajlasz
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Let $I$ isbe an arbitary index set, $((A_i)_i,\|.\|_i)$$((A_i)_i,\|.\|_i)_{i\in I}$ be a family of Banach algebras, with approximate diagonal $(m^{i}_α)_α\subseteq A_i\hat\otimes A_i$, and $B=\{(x_i)_i\in {\displaystyle \prod _{i}}A_i|\sum_i\|x_i\|_i<\infty\}$, where $I$ is an arbitary index set$B=\{(x_i)_i\in {\displaystyle \prod _{i\in I}}A_i|\, \sum_i\|x_i\|_i<\infty\}$.
  Is there any approximate diagonal for $B$?

My idea: For finite subset ‎‎$‎‎‎‎F‎‎\subseteq I‎$‎ we define ‎$‎E_F‎$‎‎‎ as below ‎‎‎‎‎ ‎
$$(‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else ‎}}$$$$ (‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else. ‎}} $$‎‎ thenThen $(‎E_F)_{F}$ is an approximate diagonal for $B$., ‏where partial order is definddefined as ‎‎‎‎‎$F_1‎\preceq F_2$ ‏if and only if $ ‎F_1\subseteq F_2‎$‎‎‎‎. Am isI right? ifIf yes, how can I prove that $\pi((‎E_F)_‎{i})a-a\to 0$ in norm.?

Here, $\hat{\otimes}$ denotes the projective tensor product of Banach spaces and $\pi\colon B\hat\otimes B\to B$ defindedis defined by $\pi(a\otimes b)=ab$.

Let $I$ is an arbitary index set, $((A_i)_i,\|.\|_i)$ be a family of Banach algebras, with approximate diagonal $(m^{i}_α)_α\subseteq A_i\hat\otimes A_i$, and $B=\{(x_i)_i\in {\displaystyle \prod _{i}}A_i|\sum_i\|x_i\|_i<\infty\}$, where $I$ is an arbitary index set.
  Is there any approximate diagonal for $B$?

My idea: For finite subset ‎‎$‎‎‎‎F‎‎\subseteq I‎$‎ we define ‎$‎E_F‎$‎‎‎ as below ‎‎‎‎‎ ‎
$$(‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else ‎}}$$‎‎ then $(‎E_F)_{F}$ is an approximate diagonal for $B$. ‏where partial order is defind as ‎‎‎‎‎$F_1‎\preceq F_2$ ‏if and only if $ ‎F_1\subseteq F_2‎$‎‎‎‎. Am is right? if yes, how can I prove that $\pi((‎E_F)_‎{i})a-a\to 0$ in norm.

Here, $\hat{\otimes}$ denotes the projective tensor product of Banach spaces and $\pi\colon B\hat\otimes B\to B$ definded by $\pi(a\otimes b)=ab$

Let $I$ be an arbitary index set, $((A_i)_i,\|.\|_i)_{i\in I}$ be a family of Banach algebras, with approximate diagonal $(m^{i}_α)_α\subseteq A_i\hat\otimes A_i$, and $B=\{(x_i)_i\in {\displaystyle \prod _{i\in I}}A_i|\, \sum_i\|x_i\|_i<\infty\}$. Is there any approximate diagonal for $B$?

My idea: For finite subset ‎‎$‎‎‎‎F‎‎\subseteq I‎$‎ we define ‎$‎E_F‎$‎‎‎ as below ‎‎‎‎‎ ‎
$$ (‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else. ‎}} $$‎‎ Then $(‎E_F)_{F}$ is an approximate diagonal for $B$, ‏where partial order is defined as ‎‎‎‎‎$F_1‎\preceq F_2$ ‏if and only if $ ‎F_1\subseteq F_2‎$‎‎‎‎. Am I right? If yes, how can I prove that $\pi((‎E_F)_‎{i})a-a\to 0$ in norm?

Here, $\hat{\otimes}$ denotes the projective tensor product of Banach spaces and $\pi\colon B\hat\otimes B\to B$ is defined by $\pi(a\otimes b)=ab$.

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Yemon Choi
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R.N
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Let $I$ is an arbitary index set, $((A_i)_i,\|.\|_i)$ be a family of Banach algebras, with approximate diagonal $(m^{i}_α)_α\subseteq A_i\hat\otimes A_i$, and $B=\{(x_i)_i\in {\displaystyle \prod _{i}}A_i|\sum_i\|x_i\|_i<\infty\}$, where $I$ is an arbitary index set.
Is there any approximate diagonal for $B$?

My idea: For finite subset ‎‎$‎‎‎‎F‎‎\subseteq I‎$‎ we define ‎$‎E_F‎$‎‎‎ as below ‎‎‎‎‎ ‎
$$(‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else ‎}}$$‎‎ then $(‎E_F)_‎{F}$$(‎E_F)_{F}$ is an approximate diagonal for $B$. ‏where partial order is defind as ‎‎‎‎‎$F_1‎\preceq F_2$ ‏if and only if $ ‎F_1\subseteq F_2‎$‎‎‎‎. Am is right? if yes, how can I prove that $\pi((‎E_F)_‎{i})a-a\to 0$ in norm.

Here, $\hat{\otimes}$ denotes the projective tensor product of Banach spaces and $\pi\colon B\hat\otimes B\to B$ definded by $\pi(a\otimes b)=ab$

Let $I$ is an arbitary index set, $((A_i)_i,\|.\|_i)$ be a family of Banach algebras, with approximate diagonal $(m^{i}_α)_α\subseteq A_i\hat\otimes A_i$, and $B=\{(x_i)_i\in {\displaystyle \prod _{i}}A_i|\sum_i\|x_i\|_i<\infty\}$, where $I$ is an arbitary index set.
Is there any approximate diagonal for $B$?

My idea: For finite subset ‎‎$‎‎‎‎F‎‎\subseteq I‎$‎ we define ‎$‎E_F‎$‎‎‎ as below ‎‎‎‎‎ ‎
$$(‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else ‎}}$$‎‎ then $(‎E_F)_‎{F}$ is an approximate diagonal for $B$. ‏where partial order is defind as ‎‎‎‎‎$F_1‎\preceq F_2$ ‏if and only if $ ‎F_1\subseteq F_2‎$‎‎‎‎. Am is right? if yes, how can I prove that $\pi((‎E_F)_‎{i})a-a\to 0$ in norm.

Here, $\hat{\otimes}$ denotes the projective tensor product of Banach spaces and $\pi\colon B\hat\otimes B\to B$ definded by $\pi(a\otimes b)=ab$

Let $I$ is an arbitary index set, $((A_i)_i,\|.\|_i)$ be a family of Banach algebras, with approximate diagonal $(m^{i}_α)_α\subseteq A_i\hat\otimes A_i$, and $B=\{(x_i)_i\in {\displaystyle \prod _{i}}A_i|\sum_i\|x_i\|_i<\infty\}$, where $I$ is an arbitary index set.
Is there any approximate diagonal for $B$?

My idea: For finite subset ‎‎$‎‎‎‎F‎‎\subseteq I‎$‎ we define ‎$‎E_F‎$‎‎‎ as below ‎‎‎‎‎ ‎
$$(‎E_F)_‎{i}=\Big\{^{m_\alpha^{i}~~{~i\in F}}_{0~~\mbox{‎ else ‎}}$$‎‎ then $(‎E_F)_{F}$ is an approximate diagonal for $B$. ‏where partial order is defind as ‎‎‎‎‎$F_1‎\preceq F_2$ ‏if and only if $ ‎F_1\subseteq F_2‎$‎‎‎‎. Am is right? if yes, how can I prove that $\pi((‎E_F)_‎{i})a-a\to 0$ in norm.

Here, $\hat{\otimes}$ denotes the projective tensor product of Banach spaces and $\pi\colon B\hat\otimes B\to B$ definded by $\pi(a\otimes b)=ab$

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