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17 votes
Accepted

Can $Ord$ have nontrivial second-order elementary self-embeddings?

Answering this question would either require refuting choiceless large cardinals or getting close to refuting Woodin's HOD Conjecture. First, if choiceless cardinals are consistent, one cannot rule ...
Gabe Goldberg's user avatar
15 votes

Second-order ordinal definability

Since you allow arbitrary sets of ordinals in your second-order definitions, all sets will be in $\text{OD}^2$. The reason is that, for any set $x$, we can code $x$ into a set of ordinals as follows. ...
Andreas Blass's user avatar
13 votes

How special is first-order $\mathsf{PA}$?

There are several notable papers, starting with a key paper of Angus Macintyre (Ramsey quantifiers in arithmetic, Model theory of algebra and arithmetic, Lecture Notes in Math., 834, Springer, 1980), ...
Ali Enayat's user avatar
  • 17.7k
12 votes
Accepted

The "first-order theory of the second-order theory of $\mathrm{ZFC}$"

I understand your theory to be the set of all sentences in the first-order language of set theory that are true in every model of $\newcommand{\ZFC}{\text{ZFC}}\ZFC_2$. This is a perfectly sensible ...
Joel David Hamkins's user avatar
10 votes
Accepted

How special is first-order $\mathsf{PA}$?

This argument has a couple of iffy points, but I believe it does work. In this paper, Shelah introduced a logic $\mathcal{L}(Q_{\mathrm{Brch}})$ which is fully compact, has the property that any ...
James E Hanson's user avatar
9 votes

Are there structures in a finite signature that are recursively categorically axiomatizable in SOL but not finitely categorically axiomatizable?

Sure - in fact, we can find a countable (and pretty concrete) example. Let $\mathcal{N}=(\mathbb{N};+,\times)$ be the standard model of (first-order) arithmetic and let $R\subseteq\mathbb{N}^2$ be the ...
Noah Schweber's user avatar
9 votes
Accepted

Analogues of worldly cardinals for (an unusual version of) second-order $\mathsf{ZFC}$

Complementing @JasonChen's answer: Assume ZFC+$I_1$ and let $j:V_{\lambda+1}\to V_{\lambda+1}$ be elementary, so $\lambda$ is the sup of the critical sequence of $j$. Then $V_{\lambda}$ models $\...
Farmer S's user avatar
  • 9,902
9 votes
Accepted

Do second-order theories always have irredundant axiomatizations?

Here is a proof of Reznikoff’s theorem I found among my notes, not quite following Reznikoff’s proof. I stared at it for a while, and it seems to apply to second-order logic just the same; in fact, ...
Emil Jeřábek's user avatar
8 votes
Accepted

Can the forcing-absolute fragment of SOL have a strong Lowenheim-Skolem property?

Yes, and a proper class of Woodin cardinals suffices. For $n<\omega$ and $X$ a set of ordinals, $M_n(X)$ denotes the minimal iterable proper class model $M$ of ZFC with $n$ Woodin cardinals above $\...
Farmer S's user avatar
  • 9,902
8 votes

Analogues of worldly cardinals for (an unusual version of) second-order $\mathsf{ZFC}$

As discussed in the comment, Theorem 8.5 in the paper Inner Models from Extended Logics: Part 1 by Kennedy, Magidor, and Väänänen gives a consistent answer that, assuming $V=L$, models of $\mathfrak{...
Jason Zesheng Chen's user avatar
8 votes
Accepted

Failure of "directedness" for second-order logic?

The answer to the question is yes. Let $\alpha_0<\alpha_1$ be the least ordinals (in the reverse lex order, say) such that $V_{\alpha_0}$ and $V_{\alpha_1}$ have the same second order theory $T$. ...
Gabe Goldberg's user avatar
8 votes
Accepted

Compactness number for a fragment of second-order logic

I think that if you have a logic $\mathcal{L}$ which has downward Lowenheim-Skolem (for theories of arbitrary cardinality, i.e. if $T$ has cardinality $\lambda$ and $N$ is a model $A$ of size $\theta\...
Farmer S's user avatar
  • 9,902
7 votes
Accepted

Topos semantics of constructive higher order logic

Categorical logic texts such as Lambek & Scott's "Introduction to higher-order categorical logic" and Johstone's "Elephant" usually focus on the categorical side of things and ...
Andrej Bauer's user avatar
  • 48.8k
6 votes
Accepted

Can second-order logic identify "amorphous satisfiability"?

Here's a monadic example. The second-order theory of the vector space $\mathbb F_2^{\oplus\omega}$ as a vector space over $\mathbb F_2$ is second-order strongly minimal because given a finite subspace ...
Harry West's user avatar
  • 1,916
6 votes

What are the simplest sentences which might distinguish Zilber’s field from the complex numbers?

Kruckman's comment is a good answer. A counterexample to Schanuel's conjecture would be one such sentence. For example, a non-zero polynomial $p(x,y)$ with integer coefficients such that $p(\pi,e) = 0$...
Jonathan Kirby's user avatar
6 votes

Does there always exist a categorical extension of $ZFC_2$ with no set models?

Since "consistent" is a weird notion in the context of second-order set-theories and moreover we can't even directly talk about a second-order theory being true of $V$ within $V$, I think it'...
Noah Schweber's user avatar
5 votes
Accepted

Does "agreement on cardinalities" imply second-order elementary substructurehood?

No, second order logic does not have the weak test property: let $\mathfrak{B}=(\mathbb{R},{<})$ (that is, the real numbers with the only predicate being the usual "less than" order) and ...
Farmer S's user avatar
  • 9,902
5 votes
Accepted

Can a nonstandard model of $\mathsf{PA}$ be "$\Delta^1_1$-well-ordered?"

I believe you don't need this, but assume that there is a strongly inaccessible cardinal $\kappa$. Fix a first-order completion $T$ of $\mathsf{PA}$ and let $\mathcal{M}$ be a saturated model of $T$ ...
James E Hanson's user avatar
5 votes

Can second-order logic identify "amorphous satisfiability"?

The answer to both questions seems to be negative. In the language having only equality, let $T$ be any completion of the theory of a set admitting an endless linear order. This property is ...
Joel David Hamkins's user avatar
4 votes

Candidate "AEC-yielding" fragments of bad logics

It's been so long since I've seen a good AEC question on here! In fact, so long I forgot the account info that gives me enough reputation to post this as a comment. I think this will get you rather ...
Will Boney's user avatar
4 votes

Abstraction logic

These should get you started on syntax with binding: Pfenning, Eliott: Higher-Order Abstract Syntax Gabbay: Foundations of nominal techniques: logic and semantics of variables in abstract syntax ...
Andrej Bauer's user avatar
  • 48.8k
4 votes
Accepted

Are there quantifiers that require multiple "steps" to define?

The quantifier $\exists^\infty$ is not definable over $\mathcal{L}_0$. To prove it, we show that a sentence $S$ tautologised by $\exists^\infty$ is also a tautology for the "always false" ...
jmd's user avatar
  • 116
4 votes

Can there be no "surprisingly averageable" second-order sentences?

This doesn't answer your question, but gives some information that might be useful. Main Claim: ZFC + "There is a proper class of inaccessible limits of measurable cardinals" + "There ...
Farmer S's user avatar
  • 9,902
4 votes
Accepted

Can $\mathsf{Ord}$ be weakly compact from a second-order perspective?

If $\kappa$ is weakly compact and there is a wellorder of $V_{\kappa+1}$ definable over $V_{\kappa+1}$ without parameters, then second order logic is Loraxian for $V_\kappa$: the least branch through ...
Gabe Goldberg's user avatar
4 votes
Accepted

Definability in pure-second order logic

Let me try to help by explicating the argument Noah mentioned. I think this is part of logic folklore—it amounts at bottom to the facts that every permutation of a pure set is an isomorphism, and ...
Joel David Hamkins's user avatar
3 votes
Accepted

On the strength of higher-logic analogues of $\mathsf{ZFC}$ + Montague's Reflection Principle

The first chromatic cardinal is the first Mahlo cardinal. (Per the connection with the reflection in the question, I assume that in the definition, $α$ and the first argument of $c_i$ need not be ...
Dmytro Taranovsky's user avatar
3 votes
Accepted

Does second-order logic satisfy Craig interpolation for second-order languages?

This is just an expansion of Emil Jerabek's comments above; I've made it CW to avoid reputation gain, and will delete this if he posts an answer of his own. Craig interpolation can be rephrased as a &...
3 votes

Compatibility of Łośian phenomena in second-order logic

I'm not sure I have a definitive answer, but three nice observations that are too long for comments: If you relax from ultrafilters to extenders (seen as directed systems of ultrafilters), then there'...
Will Boney's user avatar
3 votes
Accepted

Vopěnka's Principle for non-first-order logics

This is a really late answer, but the answer to your question is "No." As a dual to the Theorem 6 that Thomas Benjamin mentions above (which I believe is a result of Stavi), Janos Makowsky ...
Will Boney's user avatar
3 votes

Algebraization of second-order logic

Very belatedly, I think it's worth noting that there is some work connecting higher-order logic and cylindric/etc. algebras, at least including the following: Sagi, A completeness theorem for higher ...
Noah Schweber's user avatar

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