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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.
18
votes
0
answers
486
views
What is the logical complexity of the Hodge conjecture?
The Hodge conjecture seems to me the most mysterious among the Millennium problems
(and many others). In particular, I am not sure about its logical complexity. It is not difficult to see that the …
16
votes
1
answer
3k
views
A theorem of M. Artin
If I got it right, there is a theorem due to M. Artin that on a projective complex manifold any point has a Zariski open neighbourhood which is a $K(\pi, 1)$ space.
I have two questions about it.
I …
15
votes
0
answers
666
views
Is it possible to prove Mordell's conjecture geometrically?
Let $X/k$ be a smooth curve of genus $g>1$ over a number field $k$.
By the Faltings theorem (nee Mordell's conjecture), the set of $k$ - rational points
$X(k)$ is finite. Due to the Mordell-Weil theo …
13
votes
Is $\pi_2$ algebraic?
This question is simple, and with some suggestion I can answer it myself.
As abx pointed out, for a simply connected surface $h$ is an isomorphism,
by the Hurewicz theorem. There are simply connecte …
13
votes
2
answers
851
views
Is $\pi_2$ algebraic?
Let $X$ be a smooth complex projective surface. Is the Hurewicz image $h(\alpha)\in H_2(X)$ of a homotopy class $\alpha\in\pi_2(X)$ algebraic?
11
votes
1
answer
350
views
A special case of the integer Hodge conjecture
Let $X$ be a projective complex manifold of dimension $n$.
Are torsion cohomology classes in $H^{2n-2}(X,\mathbb{Z})$ algebraic?
(We may assume, without loss of generality, that $n=3$, because of the …
9
votes
1
answer
366
views
Extending a holomorphic vector bundle: a reference request
Let $Y$ be a complex manifold, $X\subset Y$ a compact submanifold, and $E\to X$ a holomorphic vector bundle. Can $E$ be extended
to a bundle over an open neighborhood of $X$ in $Y$? (Four years a …
7
votes
0
answers
247
views
The geometric meaning of the sign in the functional equation
Let $X$ be a smooth projective variety of dimension $n=\dim X$ over a finite field $\mathbb{F}_q$. As is well known, its zeta function satisfies a functional equation of the form
$$Z(X,q^{-n}T^{-1})=\ …
7
votes
0
answers
645
views
The Gysin map for a singular hypersurface
Let $X$ be a projective complex manifold and $Y\subset X$ be an irreducible
hypersurface. If $Y$ is smooth, there is a well known Gysin sequence.
However, even if $Y$ is not smooth, a kind of Gysin …
7
votes
1
answer
403
views
A lift of the second Chern class
Let $X$ be a complex manifold (not necessarily Kahler or even compact).
For the first Chern class $c_1(E)\in H^2(X,Z)$ of a holomorphic vector
bundle $E\to X$ there is an obvious lift to $H^1(X, O^* …
6
votes
1
answer
756
views
When is the Jacobian a product?
When is the Jacobian of a hyperelliptic curve
$$y^2=x(x-1)(x-a)(x-b)(x-c)$$
a product of two elliptic curves?
(This is a sort of reverse to
When is a product of elliptic curves isogenous to the Jaco …
6
votes
1
answer
533
views
Algebraic surfaces with no deformations
Is very well known that the only algebraic curve which admits no deformations is the projective line.
Q. What are "rigid" smooth algebraic surfaces? Is there a sensible classification?
6
votes
0
answers
351
views
Is this proof of the Appell-Humbert theorem wrong?
In the (very nice) book "Diophantine geometry" by Hindry and Silverman there is a proof of the Appell-Humbert theorem in Exercise A.5.5. I believe that it contains a serious mistake and I want to find …
5
votes
The geometry of the solution set of a symmetric equation in four symmetric matrices
This is not really an answer, but hopefully may be of help.
As David Speyer already pointed out, the problem is basically about a matrix equation
$$(X+Y+Z)^{-1}=X^{-1}+Y^{-1}+Z^{-1}.$$
Three symmetri …
5
votes
2
answers
814
views
What is the fundamental group of a hypersurface?
(A related question is this
On the fundamental group of hypersurfaces).
Let $X$ be a simply connected projective complex manifold of dimension at least 3.
Let $Y\subset X$ be a smooth hypersurface. …