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Search options not deleted user 85967
3 votes
Accepted

left ideals in Lie super algebras

The linear spans of $[a,x]$ and $[x,a]$, in a Lie superalgebra (i.e. a $\mathbb{Z}_2$-graded Lie algebra) are generally not the same (unlike the Lie algebras case): Since $\mathfrak a$ is not a grade …
Konstantinos Kanakoglou's user avatar
2 votes
Accepted

$P(1)$ strange type classical Lie superalgebras

$P(1)$ is not simple: To see why, consider the strange, type I, classical, simple, complex, LS $P(n)$, $n\geq 2$ realized as the set of complex, $(2n+2)\times(2n+2)$ matrices $\mathbf{M}$, with grad …
Konstantinos Kanakoglou's user avatar
3 votes
Accepted

Doubt in the Serre relation and the odd/even roots of a Lie superalgebra

Although i am not an expert in the topic, i did some studying on the references you provided together with Kac's monograph on Infinite dimensional Lie algebras. I do not have very clear answers to …
Konstantinos Kanakoglou's user avatar
4 votes

Kazhdan-Lusztig equivalence for Lie super-algebras

In: Kazhdan-Lustzig polynomials and character formulae for the Lie superalgebra $gl(m|n)$, J. Amer. Math. Soc. 16 (2002), 185–231, J. Brundan develops a conjecture on the characters for the irreducibl …
Konstantinos Kanakoglou's user avatar
5 votes
Accepted

Serre relations for Lie Superalgebras

The Serre relations (some authors also call them Serre-Chevalley relations) for the finite dimensional, complex, basic, classical, simple Lie superalgebras -in analogy with the Lie algebra case- rea …
Konstantinos Kanakoglou's user avatar
4 votes
Accepted

Typical and atypical modules for Lie superalgebras

Regarding the "what is happening in the super case"; yes i agree that in some sense, it has to do with the odd simple roots but i think it is deeper than that: In the case of semisimple, complex, Lie …
Konstantinos Kanakoglou's user avatar
12 votes
Accepted

Semisimple super Lie algebras

Yes there is a complete classification of finite dimensional, simple Lie superalgebras (over $\mathbb{C}$), which -up to a certain extent- goes very much in parallel with the corresponding case of Lie …
Konstantinos Kanakoglou's user avatar
5 votes
Accepted

Character formula for Lie superalgebras

I agree with the suggestion in the comments for searching the front of the math arXiv (as an entry point), because this is a quite broad and active topic (and i am not sure it can be fully covered wit …
Konstantinos Kanakoglou's user avatar
1 vote

Graph of a Lie super algebra

Classical, Simple, Complex, Lie superalgebras and Complex, Affine, Kac-Moody algebras and Complex, Kac-Moody Lie superalgebras have an associated graph -up to isomorphism- in the sense of a generalize …
Konstantinos Kanakoglou's user avatar
2 votes

Lie super algebra presentation of the Kähler identities

I did not know these identities but after a small search, i think that some relations are missing from your post: In: http://mathworld.wolfram.com/KaehlerIdentities.html some additional relations (see …
Konstantinos Kanakoglou's user avatar
1 vote

Sufficient conditions for unitarity of a representation of a Lie Superalgebra

If i have correctly understood your question, i think that the answer can be found at M. D. Gould, R. B. Zhang, Classification of all star and grade star irreps of gl(n|1), J. of Math. Phys., 31, 15 …
Konstantinos Kanakoglou's user avatar
3 votes

Hopf structure on the universal enveloping of a super Lie algebra

The notion of hopf algebras has slowly emerged from the work of topologists in the late '30's and '40's on the cohomology of compact Lie groups and their homogeneous spaces. Initially the term had bee …
Konstantinos Kanakoglou's user avatar
2 votes

Primitive elements in the universal enveloping algebra of Lie superalgebra

$\DeclareMathOperator\chr{char}$Yes this is true: Under your assumptions $\mathcal{P}(U(g))=g$. Also, since for any primitive element $x$ we have $\epsilon(x)=0$, for any grouplike element $y$ we have …
Konstantinos Kanakoglou's user avatar