Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Linear representations of algebras and groups, Lie theory, associative algebras, multilinear algebra.
4
votes
What is an obviously coordinate-independent description of the Chevellay-Eilenberg complex f...
I believe an approach that works is to define the Chevalley-Eilenberg complex as a kind of `Koszul complex over the ring of functions'. The enveloping algebra $U$ is relatively quadratic over the rin …
21
votes
Why would one expect a derived equivalence of categories to hold?
I asked a similar question to Daniel Huybrechts some time ago, in the form of "If I have a derived equivalence between two varieties, what is this telling me about the relation between the two varieti …
18
votes
1
answer
994
views
What rings/groups have interesting quaternionic representations?
Let $\mathbb{H}$ denote the quaternions. Let $G$ be a group, and define a representation of $G$ on $\mathbb{H}^n$ in the natural way; that is, its a map $\rho:G\rightarrow Hom_{\mathbb{H}-}(\mathbb{ …
15
votes
Lecture notes on representations of finite groups
I enjoyed Pavel Etingof's lecture notes for his representation theory class, which can be found here:
http://www-math.mit.edu/~etingof/replect.pdf
(there is a link to it on his website)
They move fast …
8
votes
2
answers
378
views
Relation between Lie Algebra Cohomology and Number of Relations of a Cyclic Module?
Let $\mathfrak{g}$ be a finite dimensional Lie algebra over $k$, let $U$ be its enveloping algebra, and let $M$ be a $\mathfrak{g}$-module (not necessarily finite dimensional). Call the invariant dim …
20
votes
Why is the exterior algebra so ubiquitous?
For me, the exterior algebra is the free polynomial algebra in anti-commutative variables. Of course, this begs the question, why do anti-commutative variables come up so much?
As a homological alge …