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Descriptive Set Theory is the study of definable subsets of Polish spaces, where definable is taken to mean from the Borel or projective hierarchies. Other topics include infinite games and determinacy, definable equivalence relations and Borel reductions between them, Polish groups, and effective descriptive set theory.

2 votes
Accepted

Is every convex subset of a Borel-linearly ordered space measurable?

I believe the answer is yes. (Please check this answer carefully, as this is rather outside my field. There may well be a much easier solution.) In the paper "Borel Orderings" by Harrington, Marker …
Nate Eldredge's user avatar
3 votes

Wanted: chain of nowhere dense subsets of the real line whose union is nonmeagre, or even co...

(Joel's answer appeared as I was typing this.) I think the answer is no. Suppose to the contrary there exists a nonmeager set $A \subset \mathbb{R}$ which is the union of some chain $\{K_i\}_{i \in …
Nate Eldredge's user avatar
9 votes
Accepted

measurable linear functionals are also continuous on separable Banach spaces?

If "measurable" means "Borel" or even "Baire measurable", then this is true. It's a special case of a more general result that any Borel homomorphism of Polish groups is continuous. See for instance …
Nate Eldredge's user avatar
2 votes
Accepted

Existence of a map connecting two marginals of a product measure

No. The measures $p, \bar{p}$ could be almost anything; there's nothing in the given conditions that forces $\bar{p}$ to be a possible pushforward of $p$. As an extreme example, take $X = \{0\}$ to …
Nate Eldredge's user avatar
3 votes

Does every separated measurable space embed into a power of $\{0,1\}$?

As in Joseph Van Name's comment, let $X$ be an uncountable set and $\Sigma$ the $\sigma$-algebra of all countable and cocountable sets. Then $(X,\Sigma)$ is separated. First note that $(X,\Sigma)$ …
Nate Eldredge's user avatar
4 votes

A non-Borel union of unit half-open squares

(This addresses a misinterpretation of the question, where $p$ can be chosen. I'll try to fix it.) This seems too easy, so maybe I've misunderstood the question, but: let $L$ be the diagonal line $\ …
Nate Eldredge's user avatar
4 votes

Meager subspaces of a Banach space and weak-* convergence

Update: Here is a ZFC (probably even ZF+DC) counterexample for Q1. It's from probability and kind of indirect, maybe someone will be able to find something shorter. Let $X = C_0([0,1])$, the space …
Nate Eldredge's user avatar
1 vote
Accepted

Meager subspaces of a Banach space and weak-* convergence

The answer to Q2 is No. I am grateful to Damian Sobota for drawing my attention to the following paper: Darst, R. B. On a theorem of Nikodym with applications to weak convergence and von Neuman …
Nate Eldredge's user avatar
5 votes
Accepted

A question about Borel sets on the unit interval

Unless I'm missing something, your measures $d\phi$ are precisely the atomless finite Borel measures (equivalently, Baire measures) on $[0,1]$. Then your condition on $A$ is that it is universally m …
Nate Eldredge's user avatar
20 votes
Accepted

Is there a Borel subset of $ \mathbb{R}^{2} $, with finite vertical cross-sections, whose pr...

No, no such set exists. This is a special case of the Lusin–Novikov theorem; see e.g. Kechris, Classical Descriptive Set Theory, Theorem 18.10. In general, let $X,Y$ be standard Borel spaces, and s …
Nate Eldredge's user avatar