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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.

125 votes

How to memorise (understand) Nakayama's lemma and its corollaries?

Mnemonic: $\quad M=IM \Rightarrow m=im$ The version of Nakayama described: If $I$ is an arbitrary ideal of an arbitrary commutative ring $A$ and if a finitely generated module $M$ satisfies $M=IM$, …
Georges Elencwajg's user avatar
114 votes

equivalence of Grothendieck-style versus Cech-style sheaf cohomology

Dear Victoria: here is a summary of the main comparison results I know of between Grothendieck cohomology (which is usually just called cohomology and written $\newcommand{\F}{\mathcal F}H^i(X,\F)$ …
Georges Elencwajg's user avatar
110 votes

Did Bourbaki write a text on algebraic geometry?

Wrong! Here is Bourbaki document on algebraic geometry, taken from the now available Master's Archives: click on Autres rédactions, then on Chap.I Théorie globale élémentaire (91 p.) This prelimina …
Georges Elencwajg's user avatar
75 votes
4 answers
6k views

When is a singular point of a variety ($\mathcal{C}^\infty$-) smooth?

If $X$ is a nonsingular algebraic (or analytic) variety over $\mathbb C$ or $\mathbb R$ then it is certainly $C^\infty$ over the reals. The converse is false for a silly reason : in the real or comp …
Georges Elencwajg's user avatar
75 votes

Etale cohomology -- Why study it?

a) Conceptually an algebraic topologist should be interested in étale cohomology, because it answers a very naïve question: given an algebraic variety over $\mathbb C$, how do I calculate algebraicall …
Georges Elencwajg's user avatar
72 votes
3 answers
8k views

Where do all these projection formulas come from?

I have been intrigued for a long time by the formal similarity of results from different areas of mathematics. Here are some examples. Set theory Given a map $f:X\to Y$ and subsets $X' \subset X, Y'\ …
Georges Elencwajg's user avatar
70 votes

What elementary problems can you solve with schemes?

If $I,J \subset A$ are comaximal ideals in a commutative ring $A$, i.e. $I+J=A$, then for all $n,m \in \mathbb N$ the ideals $I^n$ and $J^m$ are also comaximal. Proof: $\emptyset= V(A)=V(I+J)=V(I)\ …
65 votes
1 answer
4k views

Did Bourbaki write a text on algebraic geometry?

Certainly Bourbaki never wrote an introduction to algebraic geometry: we would have heard about it, right?
Georges Elencwajg's user avatar
64 votes
Accepted

Kahler differentials and Ordinary Differentials

Let $M$ be a differentiable manifold, $A=C^\infty (M)$ its ring of global differentiable functions and $\Omega^1 (M)$ the A-module of global differential forms of class $C^\infty$. The A-module of …
Georges Elencwajg's user avatar
57 votes

flatness in complex analytic geometry

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ …
Georges Elencwajg's user avatar
43 votes

Simplest examples of nonisomorphic complex algebraic varieties with isomorphic analytifications

Dear Ravi, maybe the simplest example is one by Serre: the holomorphic Stein surface $\mathbb C^\ast\times \mathbb C^\ast $ underlies two non-isomorphic smooth complex algebraic varieties. 1) $\math …
Georges Elencwajg's user avatar
43 votes

What should be learned in a first serious schemes course?

Since in 2007-2008 you evoked [ Class 24, §1.8, The problem with locally free sheaves] the equivalence between locally free sheaves and vector bundles on a scheme, the following point, potentially co …
42 votes
Accepted

Isomorphism between varieties of char 0

This is false. Consider a characteristic zero field $k$ and the cusp $C\subset \mathbb A^2_k$ with equation $y^2=x^3$ . Its normalization $n: \mathbb A^1_k \to C: t\mapsto (t^2, t^3)$ is biject …
Georges Elencwajg's user avatar
42 votes
6 answers
6k views

Arbitrary products of schemes don't exist, do they?

Thinking of arbitrary tensor products of rings, $A=\otimes_i A_i$ ($i\in I$, an arbitrary index set), I have recently realized that $Spec(A)$ should be the product of the schemes $Spec(A_i)$, a prior …
Georges Elencwajg's user avatar
40 votes
1 answer
3k views

Is every connected scheme path connected?

Every (?) algebraic geometer knows that concepts like homotopy groups or singular homology groups are irrelevant for schemes in their Zariski topology. Yet, I am curious about the following. Let's st …
Georges Elencwajg's user avatar

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