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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
10
votes
Index of Toeplitz Operator via Atiyah-Singer
Actually, Toeplitz operators are pseudodifferential operators of order 0. The Atiyah-Singer index theorem can be formulated in sufficient generality that the Toeplitz index theorem is a special case, …
16
votes
Accepted
An easy way to to explain the equivalence definitions of tangent spaces?
What all three definitions have in common is that they each try to capture the first order behavior of a smooth function on $M$.
The derivative of a smooth function $f$ along a curve $\gamma$ with $ …
10
votes
3
answers
646
views
Must a surface obtained by exponentiating a plane in a tangent space of a Riemannian manifol...
Perhaps this is basic knowledge in Riemannian geometry, but I can't seem to figure out the answer. Here is the precise statement of my question.
Let $M$ be a Riemannian manifold, $p$ a point in $M$. …
5
votes
1
answer
2k
views
Maurer-Cartan 1-form as a connection 1-form
As MO questions go, this one might be borderline - I'm guessing it could be a homework problem in a suitably advanced differential geometry class. I tried asking on math.stackexchange yesterday and i …
8
votes
Accepted
Does positive scalar curvature imply vanishing of the simplicial volume on a closed Riemanni...
In a preliminary version of what would become Gromov's "A Dozen Problems, Questions and Conjectures about Positive Scalar Curvature", he writes on page 88:
Neither is one able to prove (or disprov …
12
votes
Accepted
Sectional curvature and Gauss curvature
There is no standard / classical definition of Gaussian curvature except for surfaces embedded in $\mathbb{R}^3$. I think the pattern of exposition that the OP is asking about is really just an allus …
9
votes
Connection 1-form on a principal bundle, uniqueness of the separation of tangent space?
Your definition is a sort of hybrid of two standard definitions of connection 1-form. These are:
A connection 1-form is a Lie-algebra valued 1-form $\omega$ which satisfies $\omega(A^\#) = A$ for a …
52
votes
1
answer
17k
views
Atiyah's May 2018 paper on the 6-sphere
A couple years ago Atiyah published a claimed proof that $S^6$ has no complex structure. I've heard murmurs and rumors that there are problems with the argument, but just a couple months ago he appar …
2
votes
Curvature and Failure to return to starting point
Your question reminds me of the following result: let $X$ and $Y$ be tangent vectors in $T_p M$ such that $|X \wedge Y| = 1$ and let $\gamma$ be the exponential of a piecewise smooth closed curve in $ …
4
votes
deRham cohomology of $S^n$ without Mayer-Vietoris
For any connected and oriented $n$-manifold $M$, the sequence:
$$\Omega_c^{n-1}(M) \to \Omega_c^n(M) \to \mathbb{R} \to 0$$
is exact, where the first map is $d$ and the second map is $\int_M$. A deta …
5
votes
Can one use Atiyah-Singer to prove that the Chern-Weil definition of Chern classes are $\mat...
My first remark about this question is a little bit pithy - the standard cohomological index formula works only for even dimensional manifolds while Chern-Weil theory is of course more general.
For …
9
votes
Maxwell's equations and differential forms
I really strongly recommend chapter 2 of Naber's "Topology, Geometry, and Gauge Fields: Interactions". In this book and its companion volume "Topology, Geometry, and Gauge Fields: Foundations", Naber …
14
votes
Accepted
Must a manifold covered by $ S^n $ admit a metric of constant positive sectional curvature?
Hitchin showed (here, I think) that there is an exotic sphere which admits no metric of positive scalar curvature. This manifold certainly has the sphere as its topological universal cover, but its s …
24
votes
5
answers
6k
views
Curvature and Parallel Transport
Here is an updated formulation of the question, which is more precise and I think completely correct:
Suppose $M$ is a Riemannian manifold. Pick a point $p$ in $M$ and let $U$ be a neighborhood of th …
23
votes
1
answer
1k
views
What are some geometric reasons why a Dirac operator would have a gap in its spectrum?
My question is motivated by the following well-known computation. Let $M$ be an even dimensional Riemannian spin manifold and let $D$ be the spinor Dirac operator on $M$. Lichnerowicz showed that $D …