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The Chevalley group is a way, uniform over all fields (and commutative rings), to define a split simple algebraic group of a given type.

7 votes
Accepted

For $G$ an adjoint Chevalley group, are all of $G(\mathbb Z)$'s finite-index subgroups congr...

Chapter VI of my old Springer Lecture Notes in Mathematics 789 Arithmetic Groups (1980) is in English and gives a version of H. Matsumoto's and C. Moore's arguments for the subgroups of $\operatorname …
მამუკა ჯიბლაძე's user avatar
4 votes

Diagonal automorphisms for twisted Chevalley groups

First of all, I'd inquire what role the characteristic of the field plays here. It's true that the finite twisted groups rely on characteristics 2, 3 especiallu, but infinite twisted groups include …
Jim Humphreys's user avatar
3 votes

How to prove that Chevalley groups over $\mathbb R$ have no compact factors

There are probably multiple ways to see that $G(\mathbb{R})$ is non-compact when $G$ is a Chevalley group (in either the narrow sense of Chevalley or the broader sense of Steinberg's lectures). One …
YCor's user avatar
  • 63.9k
2 votes

Character of a semisimple connected Lie groups

In the original sense, Chevalley groups are generated by copies of the additive group of the field and are in fact simple as abstract groups if the field is not too small. (This was the motive for …
Jim Humphreys's user avatar
3 votes

Universal Chevalley group associated to $D_l$

The question shows some confusion but also illustrates the difficulty of working with the Spin groups (the universal groups of types $B_\ell$ and $D_\ell$). It's easier to work with the single Lie al …
Jim Humphreys's user avatar
5 votes
Accepted

Maximal torus of Chevalley group $Sp(4)$

The question is not well-formulated (for instance, it's not clear what you mean by "the right chevalley basis", and Chevalley is a proper name). Most important, your third sentence doesn't make sens …
Jim Humphreys's user avatar