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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
8
votes
Accepted
Reflex fields of Shimura varieties
The answer depends on your definition of a Shimura pair $(G,X)$.
Look in Section 2.1 of Deligne's paper.
If you assume only axioms (2.1.1.1), (2.1.1.2) and (2.1.1.3), then any number field $F$ can o …
4
votes
Galois cohomology of linear groups over local fields
@Brian Conrad: The sequence $$1 \rightarrow \mu \rightarrow Z' \times \mathcal{G} \rightarrow G' \rightarrow 1$$ is not exact in general. Namely, the kernel $\nu$ of the map
$Z' \times \mathcal{G} \ri …
15
votes
Existence of zero cycles of degree one vs existence of rational points
In addition to Jason's answer, I mention the following result, which I found out to be not known to experts (except Jason).
Theorem. Let $X$ be a homogeneous space of a connected linear algebra …
3
votes
1
answer
366
views
Rational points over completions of a number field
Let $X$ be a smooth geometrically irreducible $k$-variety over a number field $k$.
I do not assume that $X$ has a $k$-point.
Is it true that $X$ has $k_v$-points for almost all places $v$ of $k$?
3
votes
0
answers
557
views
Algebraic integer with conjugates on the unit circle
Let $\alpha$ be an algebraic integer on the unit circle in $\mathbb{C}$ such that all the conjugates of $\alpha$ lie on the unit circle. Does it follow that $\alpha$ is a root of unity?
11
votes
1
answer
318
views
Galois cohomology class of a reductive group not coming from a torus
Let $G$ be a (connected) reductive group over a perfect field $k$, and let $\xi\in H^1(k,G)$ be a cohomology class.
By a theorem of Steinberg (Serre, Galois cohomology, Appendix 1 to Chapter III, Theo …
2
votes
Hasse principle for $H^2$ of a maximal torus of a split simply connected group?
This is a partial answer inspired by comments of Jason Starr. I show that the answer is YES for $G=\mathrm{Sp}_{2n}$
(and also for the classical non-simply-connected groups $\mathrm{SO}_{2n+1}$ and $\ …
5
votes
Deligne's letter to Piatetskii-Shapiro from 1973
Find it here. (Edit: Link removed).
I hope you can read Russian. Enjoy!
Edit: Find here
another (better?) scan, also in Russian.
2
votes
Infiniteness of the Galois cohomology over a number field with coefficients in a finite Galo...
Let $k$ be a number field. Let $M$ be a nonzero finite $\mathrm{Gal}({\bar k}/k)$-module, i.e., a nonzero discrete finite abelian group with a continuous action of $\mathrm{Gal}({\bar k}/k)$.
Theor …
10
votes
Accepted
Galois cohomology class of a reductive group not coming from a torus
$\newcommand{\la}{\langle}\newcommand{\ra}{\rangle}$The following example is due to Vladimir Chernousov (private communication).
Let $K={\Bbb Q}(x,y,x',y')$, where $x,y,x',y'$ are variables.
Consider …
7
votes
1
answer
237
views
Hasse principle for $H^2$ of a maximal torus of a split simply connected group?
Let $k$ be a number field, and let $G$ be a split simply connected algebraic group over $k$.
Let $\Omega_k$ denote the set of places of $k$.
Let $T$ be a maximal torus of $G$ (defined over $k$). Cons …
3
votes
Diophantine equation with no integer solutions, but with solutions modulo every integer
See Subsection 6.4.1 in my paper with Zeev Rudnick Hardy-Littlewood varieties and semisimple groups, Invent. Math. 119 (1995), 37-66, page 62 (or this PDF file, page 23).
The equation is:
$$
-9x^2+2x …
1
vote
0
answers
70
views
A possible generalization of Brauer's theorem about the prime factors of the period and inde...
Let $K$ be an arbitrary field, and let $K^s$ be a fixed separable closure of $K$.
Let $F/K$ a be a finite Galois extension in $K^s$.
Let $n>0$ be a natural number.
Let $A$ be a central simple algebra …
2
votes
1
answer
86
views
Cyclic extensions of a number field of full local degree in a given set $S$
Let $K$ be a number field, and let $S=S_f\cup S_{\mathbb R}\cup S_{\mathbb C}$
be a finite set of places of $K$, where $S_f$ denotes the set of finite places in $S$, $S_{\mathbb R}$ denotes the set of …
8
votes
Accepted
Group cohomology question, trivial Galois action on discrete Galois module means we can say ...
If the $G_K$-action on $M$ is trivial, then
$$H^1(K,M)=\mathrm{Hom}(G_K,M),$$
and by Chebotarev's density theorem
$$ F^1(K,M)=0.$$
For details see Lemma 1.1(i) of Sansuc, J.-J. Groupe de Brauer et ari …