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Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.

24 votes
3 answers
2k views

Spin group as an automorphism group

Consider the real algebraic group $SO(p,q)$, this is the automorphism group of the vector space $\mathbb{R}^n$ of dimension $n=p+q$ over $\mathbb{R}$, endowed with the diagonal quadratic form with $p …
Mikhail Borovoi's user avatar
16 votes

Non-isomorphic complex Lie groups with the same exceptional Lie algebra for $\mathfrak{g_2,f...

I prefer to use the language of algebraic groups. All algebraic groups and Lie algebras are defined over $\Bbb C$. 1. Let ${\mathfrak g}$ be a semisimple Lie algebra. Consider the automorphism group $ …
Mikhail Borovoi's user avatar
16 votes
Accepted

In a compact lie group, can two closed connected subgroups generate a non-closed subgroup?

The abstract subgroup generated by $H$ and $K$ is closed. We may assume that $G$ is connected. The groups $G$, $H$, $K$ are the groups of real points of real algebraic groups $\mathbf{G}$, $\mathbf{H …
Mikhail Borovoi's user avatar
14 votes

Is there a formula for the Frobenius-Schur indicator of a rep of a Lie group?

Let us write the Frobenius-Schur indicator of the representation $V$ with highest weight $\lambda$ as $\mathrm{FS}(\lambda)$. Let $R$ denote the root system, and let $\Pi=\{\alpha_1,\dots,\alpha_l\}$ …
Mikhail Borovoi's user avatar
11 votes

Does $SU(N)$ have pseudo-real representation?

Let $G$ be a compact (anisotropic) real algebraic group. Let $\rho\colon G\to {\rm GL}(n,{\mathbb{C}})$ be a complex linear (polynomial) representation of $G$. Following OP, we say that $\rho$ is pse …
Mikhail Borovoi's user avatar
9 votes
Accepted

About the conjugation of semi-simple subgroups

The answer is YES. It suffices to assume that $H_1$ and $H_2$ are conjugate over $\mathbb{C}$ or, what is the same, that they are conjugate over $\overline{\mathbb{Q}}$. Theorem 1. Let $G$ be a co …
Mikhail Borovoi's user avatar
9 votes

Real Lie groups versus real linear algebraic groups: differences in connexity and fundamenta...

In the book Lie groups and algebraic groups by Onishchik and Vinberg, Theorem 3 in Section 5.2.1 on page 240 says: Let $S$ be a real structure on a simply connected complex semisimple Lie group $G$. …
Mikhail Borovoi's user avatar
8 votes
2 answers
464 views

Parabolics and simple roots for a special unitary group: reference request

I am looking for a reference where the relative root system, the relative system of simple roots, and parabolic $\Bbb R$-subgroups for the real algebraic group ${\rm SU}(p,q)$ are explicitly computed. …
Mikhail Borovoi's user avatar
8 votes

When is the normalizer of the maximal torus maximal?

$ \newcommand{\g}{{\mathfrak g}} \newcommand{\h}{{\mathfrak h}} \newcommand{\t}{{\mathfrak t}} \newcommand{\C}{{\mathbb C}} \newcommand{\Ad}{{\rm Ad}} \newcommand{\ad}{{\rm ad}} $Theorem. Let $G$ be …
Mikhail Borovoi's user avatar
7 votes
Accepted

Conjugacy classes of involutions in compact simple Lie group

For the case of a connected semisimple compact Lie group $G$, see this preprint, Section 3, where, following ideas of Kac and Vinberg, we describe set of conjugacy classes of $n$-th roots of a given …
Mikhail Borovoi's user avatar
7 votes

different Shimura data with common underlying group?

The question is essentially about ${\mathbf{R}}$-groups, so we shall assume that $G$ is defined over $\mathbf{R}$. It is not true that for a given connected reductive ${\mathbf{R}}$-group $G$, there …
Mikhail Borovoi's user avatar
7 votes
2 answers
666 views

Élie Cartan's paper "Les groupes réels simples, finis et continus" of 1914

Question 1. Does Élie Cartan's paper Les groupes réels simples, finis et continus, Ann. Sci. École Norm. Sup. (3) 31 (1914), 263–355 contain a classification of $\Bbb C$-linear involutions of simple …
Mikhail Borovoi's user avatar
7 votes
2 answers
715 views

What does a homogeneous space of a linear algebraic group know about the group?

Let $X=G/H$, where $G$ is a connected linear algebraic group over the field $\mathbf{C}$ of complex numbers and $H\subset G$ is an algebraic subgroup. In general, we can write the algebraic variety $X …
Mikhail Borovoi's user avatar
7 votes
Accepted

Compact dual of a noncompact Lie group

(0) The group ${\rm Aut}(\mathfrak{g}_0)$ does not have to be connected (even over $\mathbb C$), take $\mathfrak{g}_0=\mathfrak{su}(2,2)$ as a counter-example. So let $G={\rm Inn}(\mathfrak g_0)$, tha …
Mikhail Borovoi's user avatar
7 votes
2 answers
228 views

Non-semisimple symmetric subgroups of simply connected simple algebraic groups

Let $G$ be a simply connected simple algebraic group over the field of complex numbers $\mathbb C$. Let $H$ be a symmetric subgroup of $G$. This means that there exists an automorphism of order 2 $\si …
Mikhail Borovoi's user avatar

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