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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.
4
votes
universal property of the determinant bundle
How about defining det(M) as ⨁kExtkSym(M*)(O(X),Sym(M*))?
Here Sym(M*) acts on O(X) by augmentation map.
Ext and Sym are functorial, hence det should also be functorial.
10
votes
How to classify the algebras C^∞(M)?
How can we characterize the algebras (at least within all the C^∞(M)'s), that come from compact manifolds?
An algebra of the form C^∞(M) corresponds to a compact manifold if and only if all of it …
21
votes
Accepted
Real manifolds and affine schemes
(1) This is a highly productive way of looking at smooth manifolds.
It is responsible for synthetic differential geometry and derived smooth manifolds.
Both of these subjects heavily rely on this iden …
3
votes
smooth Gelfand-duality
The functor from the category of smooth manifolds to to the category of real algebras
that sends a manifold M to C^∞(M) is fully faithful, hence it is an equivalence
of categories of smooth manifolds …
3
votes
stacks that are not necessarily fibered in groupoids appearing in algebraic geometry and dif...
Virtually any kind of algebraic structure (e.g., group, ring, module, vector space, affine space, etc.) leads to a stack in categories
whose objects are bundles of such structures and morphisms are fi …
6
votes
Accepted
Do infinite products commute with trivial cofibrations, for simplicial sets?
This fact admits a much easier proof.
To show that for any simplicial fibrant sheaf F and open sets U⊆V the map F(V)→F(U) is a fibration
it suffices to show that F(V)→F(U) has a right lifting property …
3
votes
Functorial isomorphisms
Since Čech cohomology is mentioned, I presume that $C$ is the category of open subsets of a topological space.
More generally, we can assume $C$ to be an arbitrary site.
In this case, the answer to bo …
5
votes
Accepted
Stack associated to Lie group and manifold
$\underline{G}$ is the homotopy loop space of $BG$.
More precisely, the two terminal maps $G\rightarrow pt$ and $G\rightarrow pt$
yield a weak equivalence $\underline{G} \rightarrow pt\times_{BG} pt …
11
votes
Accepted
Putting sheaves to work for algebraic topology?
For sufficiently nice topological spaces $X$ (e.g., locally connected for the last two categories to be equivalent, and semilocally simply connected and locally path-connected for all three to be equi …
2
votes
Sheaf of Kähler differentials for complex manifold
Question: does the vector bundle generated by this sheaf on X∖Sing is isomorphic to the cotangent bundle on X∖Sing is ? If not what is the sheaf we should define on X to get the cotangent bundle on X …
5
votes
0
answers
430
views
Is the pushout of smooth varieties along a smooth closed subvariety again a variety?
The following question is motivated by a desire to find a rough analog in algebraic geometry of the usual notion of gluing of smooth bordisms.
Suppose k is an algebraically closed field of characteri …
10
votes
Localic or topos-theoretic definition of $\operatorname{Spec}$
Is there a construction of the spectrum of a ring, where it is defined as a locale or Grothendieck site generated by the D(f), and where the relation that D(fk)=D(f) is definitional?
Yes, the Zarisk …
11
votes
When (why) did we allow manifolds to be non-Hausdorff and/or non-second countable?
The étale space construction produces non-Hausdorff and nonparacompact spaces (e.g., smooth manifolds)
in many practical examples that have nothing to do with algebraic geometry.
The étale space is …
3
votes
What is the space of maps between superplane $\mathbb{R}^{0|2}$ and a smooth manifold $M$?
The manifold $\def\Hom{\mathop{\rm Hom}}\def\R{{\bf R}}\Hom(\R^{0|2},M)$ is isomorphic to the pullback of the parity-reversed bundle vector bundle $TM⊕TM$ along the projection map $TM→M$.
This is Lemm …
6
votes
Accepted
Is there a Čech-like way of computing $H^\bullet(X,M^\bullet)$ or even $\mathsf{R}f_* M^\bul...
Is there a Cech-like way of describing the (hyper)cohomology H∙(X,M∙) or, even better, the complex Rf∗M∙ for some map f?
Yes, the Verdier hypercovering theorem allows one to compute sheaf cohomology …