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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
10
votes
Accepted
Twin primes for polynomials in $\Bbb Z[X]$
Use the Chinese remainder theorem to construct infinitely many $f_i$ such that $f_i$ is Eisenstein at one prime, and $f_i+g$ is Eisenstein at another.
1
vote
Positive integers $n$ that divide $\sigma_2(n)$
Here are some partial results. I hope that they will help narrow down the search for counterexamples. Suppose that $pq^2=n|\sigma_2(n)=1+p^2+q^2+p^2q^2+q^4$.
Claim 1: We must have $q\equiv 1\pmod 4$. …
21
votes
Accepted
Number fields with same zeta function?
All constructions of pairs of arithmetically equivalent number fields arise in the following way: start with a Galois extension $F/M$ with Galois group $G$, let $H$, $H'$ be two subgroups that give ri …
6
votes
Accepted
Algebraic aspects of the Goldbach conjecture
You might be interested in this article on Goldbach over function fields. The approach is rather geometric/algebraic, so it does pass your "steers away from hard analysis" test.
14
votes
Heuristics of Cohen-Lenstra-Martinet
The answer to the question as stated is "no". The original Cohen—Lenstra—Martinet heuristics say nothing about the $2$-Sylow subgroup of the class group of a quadratic field.
These heuristics were lat …
3
votes
Isomorphism related to the first cohomology group
Each of the quotients in your expression is 0, so yes, there is an isomorphism, but it's between trivial groups. Here is the proof: for a Galois extension $K/\mathbb{Q}$, write down the short exact se …
5
votes
Cohen-Lenstra heuristics for totally complex fields
The general heuristic goes as follows (see the original paper by Cohen-Martinet, but I am being a bit more conservative, since some primes that Cohen-Lenstra-Martinet called "good" seem to not be all …
7
votes
Accepted
Does the unit index divide the degree of an extension of number fields?
No, not necessarily. For example, you can take $K\neq \mathbb{Q}$ to be totally real, and take $L$ to be a quadratic CM extension of $K$ whose unit group is equal to that of $K$ (e.g. make sure that $ …
3
votes
Classifying binary quadratic forms by the set of representable squares
No, the set $S_f$ is empty for lots of forms. For example, if $a$ is not a square modulo $b$, then $ax^2+by^2$ is never a square (consider the equation modulo $b$). Thus, $S_f$ is empty for $f(x,y)=6x …
6
votes
Accepted
Independence of Chebotarev densities
As stated, this is false: take $L$ and $M$ to be two distinct intermediate cubic subfields of a Galois $S_3$-extension. In particular, they are isomorphic. If a prime of $K$ splits completely in one, …
45
votes
Accepted
Has Fermat's Last Theorem per se been used?
Corollary 3.17 in this paper of Stefan Keil uses FLT for exponent 7 to show that if $E/\mathbb{Q}$ is an elliptic curve with a rational 7-torsion point $P$, and $E\rightarrow E'$ is the 7-isogeny with …
4
votes
Examples of Using Class Field Theory
As I have written in your question on SE, if you want to know how to actually compute polynomials that give you ring class fields for a given modulus, then Cohen's Advanced Topics in Computational Num …
6
votes
Accepted
How locally ubiquitous are totally real fields?
The answer to the first question is "yes". See this paper of the Dokchitser brothers, Lemma 3.1 for the case where $K/\mathbb{Q}_p$ is Galois. In the general case, apply the result to the Galois closu …
7
votes
Accepted
Does the equality of ranks imply equality of analytic ranks?
In general, it does not seem to be any easier to compare two elliptic curves than to say something about each individual curve. In other words, the only results in the direction that you are asking ab …
6
votes
Sidon Sets and Diophantine Equation
Such $X$ do indeed exist, and are explicitly constructed in I.Z. Ruzsa, Solving a linear equation in a set of integers, Acta Arith., LXV.3 (1993), pp. 259-282, Theorem 7.5. The whole paper is devoted …