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Galois theory, named after Évariste Galois, provides a connection between field theory and group theory. Using Galois theory, certain problems in field theory can be reduced to group theory, which is, in some sense, simpler and better understood.

6 votes
Accepted

Are all solvable groups *regularly* realizable over Q(x)?

It is known that all finite abelian groups are regularly realisable over $\mathbb{Q}(x)$. See e.g. B.H. Matzat, Konstruktive Galoistheorie, p. 224, M. Fried and M. Jarden, Field Arithmetic, Lemma 24.4 …
Alex B.'s user avatar
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3 votes

Isomorphism related to the first cohomology group

Each of the quotients in your expression is 0, so yes, there is an isomorphism, but it's between trivial groups. Here is the proof: for a Galois extension $K/\mathbb{Q}$, write down the short exact se …
Alex B.'s user avatar
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7 votes

What evidence is there that $\mathbb{Q}^{ab}$ is ample?

It seem like most of the evidence is rather indirect. The ampleness of $\mathbb{Q}^{ab}$ would settle other open conjectures/questions: By a result of Pop, it would imply the following conjecture of …
Alex B.'s user avatar
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5 votes

What (permutation) groups can occur as galois groups of irreducible polynomials of degree n

This question is ambiguous and can be understood in various ways, since no mention is made of the base field. If you are asking "for what subgroups $G$ of $S_n$ do there exist fields $L,K$ such that $ …
Alex B.'s user avatar
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3 votes
Accepted

Proof of a Simple Converse in Algebraic Number Theory

If you throw in the residue degrees as well, then you get Zev's question. Otherwise, the converse is not true. As an example, consider a quadratic field that has an unramified everywhere $A_5$ Galois …
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1 vote

Congruences mod primes in Galois extensions

Edit: sometimes you do get the congruence you want for traces. See corrected answer: to say that $a\equiv b \; ({\rm mod}\;{\mathfrak P})$ is equivalent to saying $a-b \in {\mathfrak P}$, so that ${\ …
Alex B.'s user avatar
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8 votes

Galois embedding question for dihedral groups

The answer is "no", in general, since there may be local obstructions. Suppose, for example, that $k$ and $n$ are odd prime powers, and let $L/\mathbb{Q}$ be the unique intermediate quadratic in $F$. …
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4 votes
Accepted

Dihedral extension unramified at primes dividing order of group?

$\DeclareMathOperator\Gal{Gal}$The answer is "yes", and this is an easy exercise in class field theory: if, for example, $q$ is a prime number that is $1\pmod n$, and $F$ is a quadratic number field i …
Alex B.'s user avatar
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4 votes

Is it possible to recover the degree of a field extension from a list of elements and the gr...

To put this one to rest, I will answer the more precise question that, after much prodding, we got Adam to formulate in the comments. I am merely paraphrasing a comment of Qiaochu. If you are given t …
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3 votes

Why is every quadratic subfield of a Galois extension of the rationals with the quaternions ...

Here is a solution using some representation theory of the quaternions and Dirichlet's theorem on the units: the quadratic subfields of our quaternion extension (call it $F$) are of the form $\mathbb{ …
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3 votes
Accepted

Local factors determine Weil representations - proof of the cyclic case

Why is the map ${\rm Gal}(FL/L)\to {\rm Gal}(F/K)$ injective? Elements of ${\rm Gal}(FL/L)$ are automorphisms of $FL$ that act trivially on $L$. To be in the kernel of the above map means to also act …
Alex B.'s user avatar
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