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Questions on group theory which concern finite groups.

35 votes
6 answers
5k views

Character-free proof that Frobenius kernel is a normal subgroup?

The question is in the title, but here is some background/reminders: A subgroup $H\neq\{1\}$ of a finite group $G$ is called a Frobenius complement if $H\cap H^g = \{1\}$ for all $g\in G\backslash H$ …
7 votes

Classifications of finite simple objects

Central simple algebras over local and global fields are classified up to Morita equivalence by class field theory.
Martin Sleziak's user avatar
7 votes
Accepted

Wedderburn decomposition of special linear groups

$\DeclareMathOperator\M{M}\DeclareMathOperator\Gal{Gal}\DeclareMathOperator\End{End}$As has been mentioned in the comments, the question for algebraically closed fields of characteristic $0$ is equiva …
Alex B.'s user avatar
  • 13k
16 votes
2 answers
2k views

Groups with all normal subgroups characteristic

Today in my research, I had to use fairly explicitly the rather tautological property of finite cyclic groups that every normal subgroup is characteristic, i.e. fixed by all automorphisms. This got me …
16 votes
Accepted

Finite groups with integral character table

There is no complete classification, but some structural results are known. To give you something to search for: such groups are called $\mathbb{Q}$-groups. There is a whole book devoted to their stru …
Alex B.'s user avatar
  • 13k
5 votes
Accepted

Irreducible and faithful $\operatorname{PSL}_2(q)$-module

The answer is "no", since for every sufficiently large prime $p$ there are simple non-trivial $\mathbb{F}_p[{\rm PSL}_2(\mathbb{F}_{2^f})]$-modules. You can take $N$ to be any such module and form the …
Alex B.'s user avatar
  • 13k
21 votes
3 answers
2k views

Number of n-th roots of elements in a finite group and higher Frobenius-Schur indicators

This is the second follow-up to this question on square roots of elements in symmetric groups and is concerned with generalisations to $n$-th roots. Let $G$ be a finite group and let $r_n(g)$ be the n …
7 votes

The zero entries in the character table of a finite group

A partial answer to Question 2: the following is a theorem of Burnside (see e.g. Isaacs, Theorem 3.8). Theorem. Let $\chi$ be an irreducible character, let $K$ be a conjugacy class of $G$, and let $g\ …
Alex B.'s user avatar
  • 13k
1 vote
Accepted

Lower bound for $[ H : H \cap xHx^{-1} ]$

You can make $[N:H]$ as big as you want: start with an arbitrary group $E$ and non-normal subgroup $H$ (e.g. $E=C_p\rtimes C_2$) dihedral of order twice a prime $p$, and $H=C_2$; for every $x\not\in H …
Alex B.'s user avatar
  • 13k
2 votes

Finding all real representations of $\mathrm{SL}_n(\mathbb{F}_q)$

$\DeclareMathOperator{\SL}{SL}\DeclareMathOperator{\GL}{GL}$To determine the real representations of a finite group, it suffices to determine the complex irreducible representations and their Schur in …
Alex B.'s user avatar
  • 13k
16 votes
Accepted

A finite group $G$ all of whose reps are defined over $\mathbb{Z}$ and yet $Rep(G)$ is not g...

The answer is no. Counterexamples include the Weyl groups of types E6, E7, and E8. For a proof that the representations of these Weyl groups are indeed all realisable over $\mathbb{Q}$ (equivalently o …
LSpice's user avatar
  • 12.9k
6 votes

Is a finite group given by its character table if its Sylow subgroups are so?

The answer to the first question is negative. The group ${\rm SL}_2(\mathbb{F}_3)$ has a $2$-Sylow subgroup isomorphic to $Q_8$, which is not determined by its character table, but ${\rm SL}_2(\mathbb …
Alex B.'s user avatar
  • 13k
47 votes
Accepted

Roots of permutations

$\DeclareMathOperator{\GL}{GL} \DeclareMathOperator{\SL}{SL}$ The maximum of the function counting square roots is attained at $x_0=1$ and this statement generalises quite well. Let $s(\chi)$ denote …
Alex B.'s user avatar
  • 13k
9 votes
Accepted

How to construct groups and large dimension representations? How about faithful ones?

In the infinite family $G_p=(\mathbb{Z}/p\mathbb{Z})\rtimes (\mathbb{Z}/p\mathbb{Z})^{\times}$, as $p$ runs over prime numbers, the bound is tight up to $O(1)$, and the representation in question is f …
Alex B.'s user avatar
  • 13k
7 votes
Accepted

Defect groups and subgroups

This is an exercise in writing out the definitions: since the defect group of $B$ is $E$, we have $B|(B_{\delta(E)})^{G\times G}$. So by assumption, $$ b\;|\;B_{H\times H}\;|\;\left((B_{\delta(E)})^{G …
Johannes Hahn's user avatar

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