Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 3377

Questions about Kähler manifolds and Kähler metrics.

4 votes
2 answers
238 views

Locality of Kähler-Ricci flow

Let $(M,I, \omega)$ be a compact Kähler manifold with $c_1(M)=0$. Denote by $\operatorname{Ric}^{1,1}(\omega)$ the Ricci (1,1)-form, that is, the curvature of the canonical bundle. It is known ("Defor …
Misha Verbitsky's user avatar
3 votes
0 answers
231 views

Kawamata BPF applied to a semi-positive line bundle using Demailly's holomorphic Morse inequ...

Let $M$ be a compact complex manifold equipped with a line bundle $L$ which has curvature which is non-negative and strictly positive outside of a measure zero set $Z$. In his paper "Holomorphic Mors …
Misha Verbitsky's user avatar
1 vote
Accepted

Can deformation equivalent Kähler manifolds always be obtained by a deformation where all th...

I don't think this is known. For hyperkahler manifolds, conjecturally, all smooth complex deformations are class C and birational to hyperkahler. If this is true, your conjecture would follow automati …
Misha Verbitsky's user avatar
2 votes
0 answers
82 views

3-Sasakian manifolds and contact Fano Kähler-Einstein manifolds

Let $(M,g)$ be a Riemannian manifold. The Riemannian cone of $M$ is $C(M) = M \times {\Bbb R}^{>0}$ with the metric $t^2 g + dt\otimes dt$. A manifold is called Sasakian if its cone is Kähler, with t …
Misha Verbitsky's user avatar
1 vote

Curvature forms of holomorphic line bundles

Sure, any closed 2-form $\eta$ with integer cohomology can serve as the curvature of a connection on a line bundle. This can be seen if you take a line bundle with the same Chern class and connection …
Misha Verbitsky's user avatar
5 votes

“Logarithmic” form of Kodaira Embedding

Sure, you should assume that there are sufficiently many functions which grow polynomially. Here is an example of such a result. THEOREM: Let $M$ be a Stein variety equipped with a Kahler metric outsi …
Misha Verbitsky's user avatar
3 votes

Can a non-Kähler complex manifold be rationally connected?

As Jason said already, there are many examples of Moishezon manifolds which are rationally connected. Indeed, any manifold bimeromorphic to a rational connected manifold is again rationally connected, …
Misha Verbitsky's user avatar
4 votes
0 answers
152 views

Calabi–Yau theorem and complex Monge–Ampère equation for transversally Kähler manifolds

Let $M$ be a compact smooth manifold, and $F\subset TM$ a smooth foliation. It is called transversally Kähler if the normal bundle $TM/F$ is equipped with a Hermitian structure (that is, a complex str …
Misha Verbitsky's user avatar
4 votes
1 answer
197 views

CSC Kahler metrics on a blown-up torus

Let $T$ be a compact torus, and $X$ its blow-up in a point (or in several points). It seems that $X$ is K-stable for any Kahler form on $X$. Is there a reference to this? Also, what can we say a …
Misha Verbitsky's user avatar
6 votes

First chern class of fibers of compact Kaehler algebraic variety

Does a nonsingular fibre $\pi^{−1}(z)$ has vanishing first Chern class? Yes. Denote a regular fiber $Z$; then $K_M|_ Z= det(N^*Z)\otimes K_Z= K_Z$ by adjunction formula. On the other hand, $K_M …
Misha Verbitsky's user avatar
6 votes
Accepted

All Kähler metrics on a complex manifold?

Let $M$ be a compact complex manifold. The set of Kahler metric on $M$ in a given Kahler class is parametrized by the set of positive volume forms with given integral, because (by Calabi-Yau theorem) …
Misha Verbitsky's user avatar
11 votes

Weitzenböck Identities

The most general version of Weitzenbock identities (with coefficients in appropriate universal enveloping algebras) is due to Uwe Semmelmann and Gregor Weingart: http://arxiv.org/abs/math/0702031 "The …
Misha Verbitsky's user avatar
5 votes

Structure of Kähler cone

Explicit description of a Kahler cone for all hyperkahler manifolds is here: https://arxiv.org/abs/1401.0479 (Rational curves on hyperkahler manifolds, Ekaterina Amerik, Misha Verbitsky)
Misha Verbitsky's user avatar
5 votes

Condition for infinite dimensional complex manifold to be Kähler by pullback form

There are three definitions of infinite-dimensional complex manifolds: strong (existence of holomorphic charts), weak (abundance of holomorphic functions) and formal (vanishing of Nijenhuis tensor). T …
Misha Verbitsky's user avatar
4 votes

Non Kähler blow-up of a Kähler manifold

When $Y$ is compact, the blow-up is always Kahler; see e.g. Lemma 3.4 in this paper (this is a generally known folklore theorem which we had to use, and hence written down). For $Y$ non-compact the …
Misha Verbitsky's user avatar

15 30 50 per page