Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Questions about Kähler manifolds and Kähler metrics.
4
votes
2
answers
238
views
Locality of Kähler-Ricci flow
Let $(M,I, \omega)$ be a compact Kähler manifold with $c_1(M)=0$. Denote by $\operatorname{Ric}^{1,1}(\omega)$ the Ricci (1,1)-form, that is, the curvature of the canonical bundle. It is known ("Defor …
3
votes
0
answers
231
views
Kawamata BPF applied to a semi-positive line bundle using Demailly's holomorphic Morse inequ...
Let $M$ be a compact complex manifold equipped with a line bundle $L$ which has curvature which is non-negative and strictly positive outside of a measure zero set $Z$. In his paper "Holomorphic Mors …
5
votes
Structure of Kähler cone
Explicit description of a Kahler cone for all hyperkahler manifolds is here:
https://arxiv.org/abs/1401.0479 (Rational curves on hyperkahler manifolds,
Ekaterina Amerik, Misha Verbitsky)
1
vote
Accepted
Can deformation equivalent Kähler manifolds always be obtained by a deformation where all th...
I don't think this is known. For hyperkahler manifolds, conjecturally,
all smooth complex deformations are class C and birational to hyperkahler.
If this is true, your conjecture would follow automati …
2
votes
0
answers
82
views
3-Sasakian manifolds and contact Fano Kähler-Einstein manifolds
Let $(M,g)$ be a Riemannian manifold. The Riemannian cone
of $M$ is $C(M) = M \times {\Bbb R}^{>0}$ with the metric $t^2 g + dt\otimes dt$.
A manifold is called Sasakian if its cone is Kähler, with t …
1
vote
Curvature forms of holomorphic line bundles
Sure, any closed 2-form $\eta$ with integer cohomology
can serve as the curvature of a connection
on a line bundle. This can be seen if you take a line bundle with
the same Chern class and connection …
5
votes
“Logarithmic” form of Kodaira Embedding
Sure, you should assume that there are sufficiently many functions which grow polynomially. Here is an example of such a result.
THEOREM: Let $M$ be a Stein variety equipped with a Kahler metric
outsi …
3
votes
Can a non-Kähler complex manifold be rationally connected?
As Jason said already, there are many
examples of Moishezon manifolds which
are rationally connected. Indeed, any
manifold bimeromorphic to a rational
connected manifold is again rationally
connected, …
4
votes
0
answers
152
views
Calabi–Yau theorem and complex Monge–Ampère equation for transversally Kähler manifolds
Let $M$ be a compact smooth
manifold, and $F\subset TM$ a smooth
foliation. It is called transversally Kähler
if the normal bundle $TM/F$ is equipped with
a Hermitian structure (that is, a complex str …
4
votes
1
answer
197
views
CSC Kahler metrics on a blown-up torus
Let $T$ be a compact torus, and $X$ its blow-up
in a point (or in several points). It seems that
$X$ is K-stable for any Kahler form on $X$.
Is there a reference to this?
Also, what can we say a …
6
votes
First chern class of fibers of compact Kaehler algebraic variety
Does a nonsingular fibre $\pi^{−1}(z)$ has vanishing first Chern class?
Yes. Denote a regular fiber $Z$; then
$K_M|_ Z= det(N^*Z)\otimes K_Z= K_Z$
by adjunction formula. On the other hand,
$K_M …
6
votes
Accepted
All Kähler metrics on a complex manifold?
Let $M$ be a compact complex manifold. The set of Kahler metric on $M$ in a given Kahler class is parametrized by the set of positive volume forms with given integral, because (by Calabi-Yau theorem) …
11
votes
Weitzenböck Identities
The most general version of Weitzenbock identities (with coefficients
in appropriate universal enveloping algebras) is due to Uwe Semmelmann and Gregor Weingart: http://arxiv.org/abs/math/0702031
"The …
5
votes
Condition for infinite dimensional complex manifold to be Kähler by pullback form
There are three definitions of infinite-dimensional complex manifolds: strong (existence of holomorphic charts), weak (abundance of holomorphic functions) and formal (vanishing of Nijenhuis tensor). T …
4
votes
Non Kähler blow-up of a Kähler manifold
When $Y$ is compact, the blow-up is always Kahler;
see e.g. Lemma 3.4 in this paper
(this is a generally known folklore theorem which we
had to use, and hence written down).
For $Y$ non-compact the …