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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
6
votes
Is there an 'unnatural' topological construction of an algebraically closed field of positiv...
This is not directly an answer to any of your questions as stated but a riff on the theme of "what does $\overline{\mathbb{F}_p}$ look like?" The best answer to this question I've found so far comes f …
16
votes
2
answers
1k
views
Which topological spaces have the property that their sheaves of continuous functions are de...
I hope I'm using the terminology correctly. What I mean is this: fix $K = \mathbb{R}$ or $\mathbb{C}$ (I'm interested in both cases). Which topological spaces $X$ have the property that for every o …
4
votes
Accepted
Is a compactly generated Hausdorff space functionally Hausdorff?
There is an example at PlanetMath of a Hausdorff space which is not completely Hausdorff / functionally Hausdorff. On the other hand it is second-countable, hence first-countable and hence compactly …
79
votes
5
answers
5k
views
Can the Lawvere fixed point theorem be used to prove the Brouwer fixed point theorem?
The Lawvere fixed point theorem asserts that if $X, Y$ are objects in a category with finite products such that the exponential $Y^X$ exists, and if $f : X \to Y^X$ is a morphism which is surjective o …
14
votes
Ultrafilters as a double dual
This is an elaboration on Todd Trimble's comment about Tom Leinster's lovely posts about codensity monads. I quite like the codensity monad story; here is my preferred way of telling it.
Suppose you …
29
votes
1
answer
2k
views
Is there a topological space X homeomorphic to the space of continuous functions from X to [...
In general, we might ask when we can find interesting spaces $X, Y$ such that $X$ is homeomorphic to $[X, Y]$. By the Lawvere fixed point theorem $Y$ must have the fixed point property. Happily, $Y = …
3
votes
Lifting symmetries to the universal cover
Assuming that $G$ is discrete, the homotopy quotient $X/G$ fits into a fiber sequence
$$X \to X/G \to BG$$
and hence, by the long exact sequence in homotopy, its fundamental group $\widetilde{G} = \ …
3
votes
Accepted
Local "pathologies" in spaces arising naturally in algebraic topology
When a certain kind of homotopy theorist says "space," they don't mean a topological space, or even an object which in any sense has an underlying topological space. The simplest translation of what " …
19
votes
Classify $K(\pi,n)$ that are manifolds
The answer is that this never happens for manifolds which are of finite type in the sense that they are homotopy equivalent to finite CW complexes. Serre showed that a simply connected finite CW compl …
8
votes
Existence of a continuous section
Asking when a continuous map $f : X \to Y$ has a continuous section is analogous to asking when a Diophantine equation over $\mathbb{Z}$ has a solution over $\mathbb{Z}$; see, for example, this blog p …
5
votes
When is the quotient by an $n$-fold loop space an $m$-fold loop space?
One way to get $G/H$ from the map $f : H \to G$ is to first deloop it, getting $Bf : BH \to BG$, and then take homotopy fibers, getting a fiber sequence
$$H \to G \to G/H \to BH \to BG.$$
This sugge …
28
votes
Does homology have a coproduct?
Here is a situation where you really use this coalgebra structure (which, as other answers have mentioned, exists over a field in particular).
If $X$ is a homotopy associative $H$-space, then $H_{\b …
6
votes
Examples of toposes for analysts
Terence Tao's cheap nonstandard analysis can be interpreted as taking place in a topos related to the topos $\text{Set}^{\mathbb{N}}$ of sets indexed by the natural numbers; see this math.SE question …
5
votes
When does a Galois connection induce a topology?
All of the Galois connections I know involving a power set arise from a relation $R : X \times Y \to 2$ as described for example here. As you observe, this relation can often be used to define a topol …
5
votes
When does a Galois connection induce a topology?
Some comments, unrelated to the other answer, on what happens in the case of the Zariski topology. Here the extra axiom is
$$V(I(S_1 \cup S_2)) = V(I(S_1)) \cup V(I(S_2))$$
(where, to fix notation, …