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11
votes
1
answer
794
views
Slicing up monads on categories with pullbacks: what are these mysterious "zerosumfree" monads"
In the case of monads, where $L$ is the free monad functor to the Eilenberg-Moore category, the Beck-Chevalley condition seems to rarely hold. … "Zerosumfree monads"? …
9
votes
2
answers
862
views
When do functors induce monadic adjunctions to presheaf categories
For a category $C$, let $C-Set$ denote the category of set-valued functors $\delta\colon C\to Set$. Given categories $C$ and $D$, and a functor $F\colon C\to D$, composition with $F$ yields a functor …
26
votes
2
answers
5k
views
What is known about the category of monads on Set?
Monads on the category Set of sets and functions are somehow fundamental objects of category theory, and moreover they have important applications to computer science. … Can we limit the three possible answers to (1),(2),(3) above for monads?
Are any other interesting facts known about $Mnd$? …
10
votes
1
answer
625
views
Reference for my monads?
I'm looking for a reference for a certain pair of monads on $Cat$. One problem is that I don't know the modern way of thinking about some basic things, so excuse me if my presentation is naive. … Is there a good reference for these monads, if they really are monads?
Thanks. …
4
votes
0
answers
125
views
Can a non-free monad have non-trivial "quine"?
(Note: some people restrict polynomial monads to be the Cartesian ones, i.e. those for which $\eta_t$ and $\mu_t$ are Cartesian natural transformations; e.g. this is the case for any free monad $\mathfrak … For this question, however, I would be happy with either Cartesian or non-Cartesian polynomial monads, as long as they are not free and have a nontrivial quine.) …
6
votes
Big list of comonads
For any monoid $(M,e,*)$ in $\mathsf{Set}$ there is a corresponding comonad $y^M$ on $\mathsf{Set}$. It sends a set $A$ to the set of morphisms into $A$ from $M$,
$$
A\mapsto A^M.
$$
Note that $y=y^1$ …