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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.
4
votes
functors reflecting "isomorphism relations"?
One paper about this is Elliott's Towards a theory of classification, where such functors are called classification functors, and there is a nice collection of examples.
(Though note that a category …
2
votes
Spans as binary relations: reflexivity, transitivity, and completeness?
This is not really an answer to your question, but I'd like to point out that your "extension" definition probably isn't quite what you want yet. Of course this may well depend on your intended applic …
4
votes
Quotient-free monoidal categories
Here are some additional thoughts and examples.
1) The argument presented in the OP applies whenever one has a monoidal category $(\mathsf{C},\otimes,1)$ in which the unit object $1$ is a separator a …
10
votes
Accepted
Why is subcoalgebra structure unique?
Let us say that a monomorphism $U\subseteq A$ is nontrivial if $U$ is nonempty. Since every nontrivial monomorphism in $Set$ is split, every $F : Set\to Set$ takes nontrivial monomorphisms to monomorp …
7
votes
Slicing up monads on categories with pullbacks: what are these mysterious "zerosumfree" monads"
Here are some remarks and pointers to the literature which are too long for a comment.
The map
$$
\mathsf{Dist}(X_1) \times_{\mathsf{Dist}(X)} \mathsf{Dist}(X_2) \longrightarrow \mathsf{Dist}(X_1 \t …
8
votes
Accepted
Strongly connected components as adjoint functor?
The existence of such an adjoint triple in particular requires the strongly connected components functor to be a left adjoint. But in fact this fact is not a left adjoint, since it doesn't preserve co …
4
votes
In which category is a measure on a measurable space a morphism?
A very natural enlargement of the category of measurable spaces is $\mathsf{Stoch}$, the category of measurable spaces and Markov kernels, with composition given by the Chapman-Kolmogorov equation. Th …
8
votes
Why Kleisli Markov categories and not the Eilenberg-Moore categories of the associated monads
What can you do with the Kleisli category (of a probability monad) that you can't do with the Eilenberg-Moore category?
The first paragraph of kirk sturtz's answer provides a good high-level summary …
8
votes
Are there noncartesian monoidal categories with $A \otimes B = A \times B$?
Note: As pointed out by
Peter LeFanu Lumsdaine in the comments, the example constructed in this answer does not work in its current form, since naturality of the associator fails. (This only affects t …
4
votes
Accepted
Algebras for probability monad
The algebras of this monad and closely related ones have been introduced by Pumplün and Röhrl. For example the introduction of a paper by Börger and Kemper provides a good summary,
Pumplün and Röhrl …
3
votes
Accepted
Symetrical simplex category
You haven't specified what the morphisms in your "symmetric simplex category" are supposed to be, and there are two natural choices:
Functors, or
Natural isomorphism classes of functors.
In the fi …
10
votes
1
answer
813
views
Tannaka duality for C*-algebras?
Tannaka-Krein
duality shows
how to recover a group $G$ from its category $\mathbf{Rep}(G)$ of finite-dimensional
complex representations and the forgetful functor $F:\mathbf{Rep}(G)\to
\mathbf{Vect}_{ …
23
votes
Accepted
Reconstructing base manifold from its category of smooth vector bundles
Yes, it is possible to recover the manifold through the following steps:
Smooth Serre-Swan theorem: $\mathbf{Vect}(X)$ is equivalent to the category of finitely generated projective modules over $C^\ …
3
votes
Accepted
Elements that commute with $1$ in the pushout of a $C^{\ast}$-algebra
The answer is yes: $1 \ast c = c \ast 1$ implies $c \in B$.
To see this, let me first translate the statement into fully categorical language. If we restrict to $\|c\| \le 1$ wlog, then the elements …
13
votes
Another notion of exactness: how to refine it, and where does it fit?
I'd like to argue that the current definition is too minimal to allow for much theory development, since the only substantial axiom is the pasting condition. In particular, it would be possible to tak …