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Questions on group theory which concern finite groups.

7 votes
1 answer
372 views

When is an almost simple group a split extension of its socle?

Here an almost simple group is a finite group whose socle (product of all minimal normal subgroups) is a nonabelian simple group. As an extension of its socle, an almost simple group could be split or …
Binzhou Xia's user avatar
0 votes
0 answers
224 views

Orbits of stabilizer of two points in a 2-transitive permutation group

I was doing something which needs to know sizes of all orbits of the stabilizer of two points in a 2-transitive permutation group. Since all 2-transitive permutation groups are known ans so are their …
Binzhou Xia's user avatar
1 vote
1 answer
104 views

The action of graph automorphism of finite symplectic group on maximal subgroups

Let $G=Sp(4,2^f)$ with $f>1$. Based on the facts when $f$ is small, I would feel the following: $G$ has two conjugacy classes of subgroups isomorphic to $SO^+(4,2^f)$. One is in Aschbacher's class C8 …
Binzhou Xia's user avatar
0 votes
0 answers
105 views

Soluble subgroups of 8-dimensional orthogonal groups over GF(4) transitive on nondegenerate ...

Let $V$ be an $8$-dimensional vector space over $GF(4)$ equipped with a nondegenerate plus type quadratic form, $G$ be an almost simple group with socle $L=\Omega^+(V)$, and $H$ be a soluble subgroup …
Binzhou Xia's user avatar
8 votes
3 answers
1k views

Exponent of Sylow $p$-subgroup of classical groups over a field of characteristic $p$

Let $G$ be a classical group of dimension $n$ over $GF(q)$ where $q=p^f$ is a prime power, and $P$ be a Sylow $p$-subgroup of $G$. What is the maximal order of elements, i.e. the exponent, of $P$? F …
Binzhou Xia's user avatar
3 votes
2 answers
471 views

Maximal soluble subgroups in a parabolic subgroup of finite classical simple group

Let $G$ be a classical simple group over a finite field $GF(q)$ and $P$ a parabolic subgroup of $G$ stabilizing an isotropic subspace. Is the Borel subgroup of $G$ maximal soluble in $P$ and is there …
Binzhou Xia's user avatar