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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.

77 votes
0 answers
4k views

2, 3, and 4 (a possible fixed point result ?)

The question below is related to the classical Browder-Goehde-Kirk fixed point theorem. Let $K$ be the closed unit ball of $\ell^{2}$, and let $T:K\rightarrow K$ be a mapping such that $$\Vert Tx-Ty\V …
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  • 4,060
12 votes
Accepted

Sequential topological vector spaces

The space of tempered distributions is sequential (for its usual strong topology). See, e.g., Dudley, and the references therein.
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  • 4,060
11 votes
Accepted

Is a subspace with a certain property dense in the dual of a vector space?

The answer is negative. Since the linear span of the Dirac masses is not a dense subspace of the dual of $C[0,1]$.
Ady's user avatar
  • 4,060
11 votes

When is a Banach space a Hilbert space?

Just two isometric/isomorphic characterizations: A Banach space $X$ is [isometric to] a Hilbert space if and only if there exists a Banach space $Y$ and a symmetric bilinear mapping $f:X\times X\righ …
Ady's user avatar
  • 4,060
11 votes
2 answers
860 views

Monotone Lipschitz embedding ?

In 1974, Aharoni proved that every separable metric space (X, d) is Lipschitz isomorphic to a subset of the Banach space c_0. Thus, for some constant L, there is a map K: X --> c_0 that satisfies the …
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  • 4,060
11 votes
1 answer
654 views

Nonseparable Hilbert spaces as quotients of spaces of bounded functions

Is the following result true: the Hilbert space $\ell^{2}\left(2^{\Gamma}\right)$ is a quotient of $\ell^{\infty}\left(\Gamma\right)$ for any uncountable $\Gamma$ ? [I think it is, but cannot remember …
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  • 4,060
9 votes
4 answers
1k views

Boundedness of nonlinear continuous functionals

Let $K$ be the closed unit ball of $C[0,1]$, and let $f$ in $C(K,\mathbb{\, R})$. Is it true that there exists an infinite dimensional reflexive subspace $E$ of $C[0,1]$ s.t. $f(K\cap E)$ is bounded ? …
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  • 4,060
9 votes
1 answer
993 views

Topological "Interpolation" ?

Let E be a normed space, and let $T$:E * $\rightarrow$ E * be a nonlinear operator. Suppose that : 1) $T$ is continuous from (E *, ||.||) to itself (i.e., it is norm-continuous). and 2) $T$ is co …
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  • 4,060
9 votes
2 answers
1k views

Borsuk pairs of Banach spaces

Given $X$, $Y$ two real Banach spaces, let's say that $(X,\ Y)$ is a Borsuk pair if for any continuous mapping $T$ : {$x$ $\in$ $X$ ; $||x||\leq1$} $\rightarrow$ $Y$ s.t. $T$ is odd on {$x$ $\in$ $X$ …
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  • 4,060
6 votes

Isomorphisms of Banach Spaces

One may also remark that $c_{0}$ $\times$ (ℓ∞$/c_{0}$) is a predual of (ℓ∞)$^*$. However, $c_{0}$ $\times$ (ℓ∞$/c_{0}$) is not isomorphic to ℓ∞.
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  • 4,060
6 votes
1 answer
723 views

The "ultimate" indefinite inner product space

This can be considered as a relative of Splitting a space into positive and negative parts. Is there a real (non-trivial) vector space $V$, endowed with a nondegenerate symmetric bilinear pairing $\l …
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  • 4,060
6 votes
1 answer
413 views

Subspaces of $L^{2}$

[In what follows $0^{0}$= 1 by convention.] Is there some closed infinite dimensional linear subspace $F$ of $L^{2}(0,1)$ such that $\left\lvert f\right\rvert^{\left\lvert f\right\rvert}$ belongs to $ …
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  • 4,060
6 votes
0 answers
639 views

Hilbert subspaces of indefinite inner product spaces

Let $E$ be a real linear space, endowed with a non-degenerate symmetric bilinear form $(.,.)$. Suppose that the [indefinite] inner product space $(E,(.,.))$ satisfies the following [sequential] prope …
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  • 4,060
5 votes
1 answer
401 views

Nonlinear Nuclear Operators ?

Is there a "right" definition of the nuclear operator in the nonlinear framework ? Of course, such an operator must be compact, while a linear operator should be "nonlinearly" nuclear iff it is nuclea …
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  • 4,060
5 votes
Accepted

Orthonormal basis for non-separable inner-product space

This is Problem 54 in Halmos' "A Hilbert Space Problem Book". However, I think this is a concrete counterexample. [Please let me know if not viewable.]
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