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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
1
vote
Extending Continuous Sublinear maps on dense subsets of a Banach space
To 1) and 2). Let $X^{'}=Y=c_{0}$ , and let $X=c_{00}$. Take some
$p\in X^{'}\smallsetminus X$, and define $T:X\rightarrow Y$ by $Tx:=\left\Vert x\right\Vert \cdot\left(\sin\left(\left\Vert x-p\right\ …
3
votes
Accepted
separability of a certain space of continuous functions
The answer is negative. For, pick some non-zero $e$ in $E$, and
choose a surjection $\rho\in C\left(O,\mathbb{R}\right)$ (there exists
!).
Next, consider the (uncountable, uniformly discrete) family …
5
votes
Accepted
Orthonormal basis for non-separable inner-product space
This is Problem 54 in Halmos' "A Hilbert Space Problem Book".
However, I think this is a concrete counterexample. [Please let me know if not viewable.]
12
votes
Accepted
Sequential topological vector spaces
The space of tempered distributions is sequential (for its usual strong topology). See, e.g., Dudley, and the references therein.
1
vote
0
answers
133
views
Square powers of hemicontinuous operators
Let H be an infinite dimensional real Hilbert space.
A [not necessarily linear] mapping of H into itself is said to be hemicontinuous if it is continuous from each line
segment of H to the weak topol …
11
votes
Accepted
Is a subspace with a certain property dense in the dual of a vector space?
The answer is negative. Since the linear span of the Dirac masses is not a dense subspace of the dual of $C[0,1]$.
11
votes
1
answer
654
views
Nonseparable Hilbert spaces as quotients of spaces of bounded functions
Is the following result true: the Hilbert space $\ell^{2}\left(2^{\Gamma}\right)$ is a quotient of $\ell^{\infty}\left(\Gamma\right)$ for any
uncountable $\Gamma$ ? [I think it is, but cannot remember …
5
votes
4
answers
1k
views
Is any continuous linear operator from a dual Banach space to a separable Hilbert space the ...
Let $E$ be an arbitrary Banach space and let $T:E^{*}\rightarrow\ell^{2}$
be a linear continuous operator. Is it true that $T$ must be the
$so$-limit (i.e., limit w.r.t. the strong operator topology) …
3
votes
How can I measure the Morse index in infinite dimensions?
It seems that simply one can't measure it. Here below is briefly described
an example of a nondegenerate indefinite inner product space having
no cardinal-valued Morse index.
Consider $(\ell^{2},<.,. …
4
votes
Radii and centers in Banach spaces
I think that http://www.ams.org/journals/tran/1982-271-02/S0002-9947-1982-0654848-2/S0002-9947-1982-0654848-2.pdf [together with its references] provides us with several counterexamples [as well as wi …
2
votes
0
answers
197
views
Generating cones having no surjections [in operator spaces]
Is this little toy known ?
Let $E$ be some Banach space, and let $K$ be the closed unit ball
of its dual, endowed with the weak-star topology. Also, let $j:E$ $\rightarrow$ $C(K)$
be the natural embe …
11
votes
When is a Banach space a Hilbert space?
Just two isometric/isomorphic characterizations:
A Banach space $X$ is [isometric to] a Hilbert
space if and only if there exists a Banach space $Y$ and a symmetric
bilinear mapping $f:X\times X\righ …
77
votes
0
answers
4k
views
2, 3, and 4 (a possible fixed point result ?)
The question below is related to the classical Browder-Goehde-Kirk fixed point theorem.
Let $K$ be the closed unit ball of $\ell^{2}$, and let $T:K\rightarrow K$
be a mapping such that
$$\Vert Tx-Ty\V …
3
votes
Show a linear operator is not compact
Let { $ L_{n} $ } be the sequence of Laguerre polynomials,
and let us define
$e_{n}(t)=\dfrac{L_{n}(\ln t)}{t}$ $\cdot\chi_{\left(1,\infty\right)}\left(t\right)$
$(n\in\mathbb{N\textrm{, t > 0}})$ …
5
votes
1
answer
494
views
On the failure of the infinite dimensional Brouwer Theorem
Let $K$ be the closed unit ball of some infinite dimensional Banach
space, and let $H$ be an autohomeomorphism of $K$, having fixed
points. Can $H/2$ be fixed point free ?
Also, let ${\mathcal{F}}$ : …