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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.

58 votes
Accepted

Are there any nontrivial abelian categories with only finitely many objects?

Take the category of (at most) countable-dimensional vector spaces over your favourite field. Then take the quotient by the Serre subcategory of finite-dimensional vector spaces. (And take a skeletal …
Jeremy Rickard's user avatar
49 votes
Accepted

Example of an unnatural isomorphism

For a simpler, but arguably more artificial, example than Mark's, take $\mathcal{C}$ to be the category with one object and two morphisms. Then the identity functor $\mathcal{C}\to\mathcal{C}$ is "unn …
28 votes
Accepted

Cocomplete but not complete abelian category

I think I have an example. Fix a chain of fields $k_\alpha$ indexed by ordinals $\alpha$, where $k_\alpha\subset k_\beta$ is an infinite field extension for all pairs $\alpha<\beta$ of ordinals. Fir …
Jeremy Rickard's user avatar
22 votes
Accepted

Example of an abelian category with enough projectives and injectives which are not dual

The category of countable abelian groups is an essentially small abelian category, and has enough projectives and injectives (the countable free abelian groups and the countable divisible groups respe …
Jeremy Rickard's user avatar
21 votes
Accepted

Grothendieck group of derived category

Yes, it's always zero, assuming $D(A)$ means the unbounded derived category. My complexes will be cochain complexes, and $X[1]$ will be $X$ shifted down in degree. First suppose $X$ is bounded below …
Jeremy Rickard's user avatar
20 votes
Accepted

Recovering an abelian category from the Ext of its simple objects

Here's a counterexample that appears in nature. Fix a prime $p$ and a field $k$ of characteristic $p$, and let $G=C_{p^{n}}$ be a cyclic group of order $p^{n}$ (where $n\geq1$ if $p$ is odd, and $n\ge …
Jeremy Rickard's user avatar
19 votes
1 answer
469 views

Vopěnka's principle and contravariant full embeddings between module categories

I was recently reminded about this old question on math.stackexchange. Let $\operatorname{Mod}R$ be the category of (right) modules for a ring $R$. The questioner mistakenly thought that the Freyd-Mit …
Jeremy Rickard's user avatar
18 votes
Accepted

Are all vector-space valued functors on sets free?

This is probably an absurdly over-complicated answer, but ... Let $$J(X)=\left\{\sum_{x\in X}a_xx\in GX: \sum_{x\in X}a_x=0\right\}.$$ I claim that $J$ is not of the form $H\circ G\circ F$. Suppos …
Jeremy Rickard's user avatar
17 votes
Accepted

Tilting Objects in BGG Categories $\mathcal{O}$

Words change their meanings. The original meaning of “tilting module” is that of Happel and Ringel in the representation theory of finite dimensional algebras, which requires the projective dimension …
Jeremy Rickard's user avatar
16 votes
Accepted

When the restriction of a derived functor to a subcategory is the derived functor of the res...

In the example where $\mathcal{D}$ is the category of abelian groups and $\mathcal{C}$ is the category of finite abelian groups, take $F(X)=X\otimes_\mathbb{Z}\mathbb{Q}/\mathbb{Z}$. Then the restrict …
Jeremy Rickard's user avatar
16 votes
Accepted

In an abelian category with no nontrivial Serre subcategories, does every short exact sequen...

The category of finite abelian $p$-groups (where $p$ is your favourite prime) is an abelian category with no proper nonzero Serre subcategories, but not every short exact sequence splits.
Jeremy Rickard's user avatar
15 votes

Are there natural examples of non-symmetric Frobenius algebras?

Here are a couple of "natural" constructions that produce Frobenius algebras over a field that are not necessarily symmetric. (A) The trivial extension algebra of any algebra $A$ is defined to be $A\ …
Jeremy Rickard's user avatar
14 votes

"Sums-compact" objects = f.g. objects in categories of modules?

If it's considered bad form to resurrect year-old threads, then please slap my wrist (gently, please; I'm new here!) A fairly simple explicit example of a "sumpact" module that is not f.g. is as foll …
Jeremy Rickard's user avatar
12 votes

Do the isomorphism classes of indecomposable objects in $R{\text{-mod}}$ form a set?

In Conjecture $1_{\infty}$ of Simson, Daniel, On large indecomposable modules, endo-wild representation type and right pure semisimple rings., Algebra Discrete Math. 2003, No. 2, 93-118 (2003). ZBL106 …
Jeremy Rickard's user avatar
12 votes

Is a retract of a free object free?

A few months after the last activity on this question, Neena Gupta gave a proof that over a field $k$ of positive characteristic, a retract of a polynomial algebra need not be a polynomial algebra: ht …
Jeremy Rickard's user avatar

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