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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.

14 votes
Accepted

Between compact and locally uniform: What is the name of this convergence?

This notion of convergence is not often refered to; I think mostly because it does not come from a topology. But this an excellent notion of convergence, probably the best we can put on the space of ( …
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10 votes
Accepted

A C*-algebra enjoying some different C*-norms

No that's not possible (except the trivial case). Any $*$-homomorphism between $C^*$-algebras is automatically contractive, and if it is injective then it is isometric. You can apply this to the ident …
Simon Henry's user avatar
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10 votes

What are the 'wonderful consequences' following from the existence of a minimal dense subspace?

I like to call this result the localic Baire category theorem, and it plays essentially the same role as Baire category theorem: it lets you "construct" object by showing that some spaces are non-empt …
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7 votes
3 answers
737 views

Duality between Banach spaces and compact convex spaces

I always had the impression that there was a duality (i.e. a contravariant equivalence of categories) between Banach spaces and certain notion of pointed compact convex set (something like algebras fo …
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6 votes
Accepted

Continuous maps on compact topological spaces which induce compact (Fredholm) operators

The image of $f$ is an interval $[a,b] \subset [0,1]$. $T_f$ induce an isometric inclusion of $C([a,b])$ in $C([0,1])$. If $T_f$ was compact then weak convergence of a bounded sequence in $C([a,b])$ …
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6 votes
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The Gelfand duality for pro-$C^*$-algebras

The answer is No. Rougly, because it is not a good idea to look at continuous $\mathbb{C}$ valued function on a space which is not completely Haussdorff as completely haussdorf is exactly the hypothes …
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6 votes
Accepted

What is the Gelfand dual of an open surjection?

After more thought, I think the correct statement is the following: Theorem: Let $\pi : X \to Y$ be a continuous map between compact Hausdorff spaces. Then the following condition are equivalents: (a) …
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5 votes
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Counterexample to Riesz representation for Hilbert modules

Take $A= \mathcal{C}([0,1])$ and $H$ the ideal of $A$ of functions that vanish at $0$. $H$ is a Hilbert $A$ module (as any ideal, with the natural multiplication of $A$ and the scalar product $(x,y)= …
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5 votes

Relation between norm of any element of $C^*$-algebra in terms of self adjoint elements

The norm of the self adjoint part is not sufficient: Even if $b$ and $c$ commutes (which should be the easiest case) then it corresponds (by looking at the commutative algebra generated by $b$ and $c$ …
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4 votes

No Hilbert space can have countable Hamel basis without using Baire's Category theorem

Nam-Kiu Tsing argument indeed become way much simpler for Hilbert spaces. In fact I wouldn't be surprise if his argument was inspired from the (very easy) case of Hilbert spaces: If you have a counta …
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4 votes

Why $A^*A =A$ implies that $A$ is a C$^*$ algebra (Proposition 5.2.8 of An Invitation to Qua...

I assume that $A^* A$ denotes the algebra generated by product $a^* b$ with $a, b \in A$, but the following argument also applies to some others interpretation of $A^* A$. If $A^* A =A$ then for any …
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4 votes

Constructive proof of existence of non-separable normed space

AS I said, it depends way to much on your framework to give a definitive answer ! here are some exemples that works in some cases: Take $E$ to be the free $\mathbb{Q}$-vector space on a set $S$, and …
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4 votes
2 answers
353 views

On the descent homomorphsim of Kasparov equivariant KK theory

Hello, I have recently read about the construction of the descent map in Kasparov KK theory, which, for a group $G$ and two $G$-equivariant $C^*$ algebra $A$ and $B$ send $KK_i^G(A,B)$ to $KK_i(A \rt …
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4 votes
Accepted

$H^{*}$ algebras as a generalization of $C^{*}$ algebras

Let assume that you consider unital algebra only (one can still study non unital algebra by unitarizing them, but notion of spectrum is always a little annoying when one want to consider non unital al …
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4 votes

Do Hausdorff locally convex inductive limits always exist?

The limit always exists whether or not $H$ is closed: The inductive limit in the category of hausdorff lc vector space will be the quotient of $F$ by the closure of of $H$: a cone for the inductive li …
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