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For question in Proof Theory, where "proofs" themselves are the object of mathematical investigation. It is not to be used to request a proof of some result.

144 votes
Accepted

Reductio ad absurdum or the contrapositive?

Although the other answers correctly explain the basic logical equivalence of the two proof methods, I believe an important point has been missed: With good reason, we mathematicians prefer a direct …
Joel David Hamkins's user avatar
44 votes
Accepted

Writing "Semi-Formal" Proofs

The question becomes interesting when it is interpreted as a technical question about the extent to which we can have a semi-formal language somehow in-between the truly formal proofs, which are large …
Joel David Hamkins's user avatar
34 votes
2 answers
2k views

What is the logical status of the sentence combining the ideas of Löb and Rosser, "this sent...

Logicians are familiar with the variety of self-referential sentences expressible in the language of arithmetic: The Gödel sentence, "this sentence is not provable", which indeed is not provable in w …
Joel David Hamkins's user avatar
28 votes

Strong induction without a base case

My example is the classical proof that sqrt(2) is irrational. More generally, many proofs that proceed by showing that there are no minimal counterexamples exemplify your phenomenon. The method of no …
27 votes
Accepted

Are there any good nonconstructive "existential metatheorems"?

Set theory provides a good example. It is often convenient in set theory to work with the concept of "classes" and treat them as mathematical objects of their own kind. The standard axiomatization of …
25 votes
Accepted

Is there a known way to formalise notion that certain theorems are essential ones?

Although your question is vague in certain ways, one robust answer to it is provided by the subject known as Reverse Mathematics. The nature of this answer is different from what you had suggested or …
24 votes

Bourbaki's epsilon-calculus notation

You must read the charming essay lampooning this notation, while also giving a thorough logical analysis of it, by Adrian Mathias. Adrian Mathias, A Term of Length 4,523,659,424,929, Synthese 133 (20 …
Joel David Hamkins's user avatar
23 votes

Independence of PA implies independence of PA union all true $\Pi_1$ statements

The claim you have asked us to prove is not true. If PA is consistent, then by the Incompleteness Theorem there are $\Pi_1$ statements that are independent of PA, such as Con(PA), which can be seen to …
Joel David Hamkins's user avatar
21 votes
Accepted

Is there a consistent arithmetically definable extension of PA that proves its own consistency?

Surprisingly, the answer is yes! Well, let me say that the answer is yes for what I find to be a reasonable way to understand what you've asked. Specifically, what I claim is that if PA is consistent …
Joel David Hamkins's user avatar
19 votes

Compactness Theorem for First Order Logic

There are indeed many proofs of the Compactness theorem. As I mention in this MO answer, when I was a graduate student Leo Harrington told me that he used a different proof method for Compactness eac …
Joel David Hamkins's user avatar
18 votes
Accepted

Deep theorems and long proofs

There is a body of very interesting work surrounding the proof complexity of various formulations of the well-known pigeon-hole principle, the fact that there is no injective function from a set of si …
Joel David Hamkins's user avatar
16 votes

When does $ZFC \vdash\ ' ZFC \vdash \varphi\ '$ imply $ZFC \vdash \varphi$?

With regard to your sub-question, Now imagine a universe where $\text{Con}(\text{ZFC})$ holds but all the models of $\text{ZFC}$ are $\omega$-nonstandard and believe $\neg \text{Con}(\text{Z …
Joel David Hamkins's user avatar
14 votes

What's a magical theorem in logic?

The Truth Lemma The result says that what's true in a forcing extension $M[G]$ is just what's forced to be true by the path of the generic filter $G$. More precisely: Suppose $M$ is a countable t …
14 votes
Accepted

Decidability of decidability

$\newcommand\Con{\text{Con}} \newcommand\Dec{\text{Dec}}$ Let $F$ be the formal system in which the proofs are to be carried out, when it comes to your formal assertions of the form $\Dec(\varphi)$. …
Joel David Hamkins's user avatar
14 votes
Accepted

Peano arithmetic vs. fast-growing hierarchy with pathological fundamental sequences

The answer is no. Choose a fundamental sequence for $\epsilon_0$ itself in the usual way, which I think is $\epsilon_0[n]=\omega^{\omega^{{\vdots}^\omega}}$, and then modify the earlier fundamental se …
Joel David Hamkins's user avatar

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