Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
For question in Proof Theory, where "proofs" themselves are the object of mathematical investigation. It is not to be used to request a proof of some result.
144
votes
Accepted
Reductio ad absurdum or the contrapositive?
Although the other answers correctly explain the basic logical equivalence of the two proof methods, I believe an important point has been missed:
With good reason, we mathematicians prefer a direct …
44
votes
Accepted
Writing "Semi-Formal" Proofs
The question becomes interesting when it is interpreted as a technical question about the extent to which we can have a semi-formal language somehow in-between the truly formal proofs, which are large …
34
votes
2
answers
2k
views
What is the logical status of the sentence combining the ideas of Löb and Rosser, "this sent...
Logicians are familiar with the variety of self-referential sentences expressible in the language of arithmetic:
The Gödel sentence, "this sentence is not provable", which indeed is not provable in w …
28
votes
Strong induction without a base case
My example is the classical proof that sqrt(2) is irrational.
More generally, many proofs that proceed by showing that there are no minimal counterexamples exemplify your phenomenon. The method of no …
27
votes
Accepted
Are there any good nonconstructive "existential metatheorems"?
Set theory provides a good example. It is often convenient in set theory to work with the concept of "classes" and treat them as mathematical objects of their own kind. The standard axiomatization of …
25
votes
Accepted
Is there a known way to formalise notion that certain theorems are essential ones?
Although your question is vague in certain ways, one robust answer to it is provided by the subject known as Reverse Mathematics. The nature of this answer is different from what you had suggested or …
24
votes
Bourbaki's epsilon-calculus notation
You must read the charming essay lampooning this notation, while also giving a thorough logical analysis of it, by Adrian Mathias.
Adrian Mathias, A Term of Length 4,523,659,424,929, Synthese 133 (20 …
23
votes
Independence of PA implies independence of PA union all true $\Pi_1$ statements
The claim you have asked us to prove is not true. If PA is consistent, then by the Incompleteness Theorem there are $\Pi_1$ statements that are independent of PA, such as Con(PA), which can be seen to …
21
votes
Accepted
Is there a consistent arithmetically definable extension of PA that proves its own consistency?
Surprisingly, the answer is yes! Well, let me say that the answer
is yes for what I find to be a reasonable way to understand what
you've asked.
Specifically, what I claim is that if PA is consistent …
19
votes
Compactness Theorem for First Order Logic
There are indeed many proofs of the Compactness theorem. As
I mention in this MO
answer,
when I was a graduate student Leo Harrington
told me that he used a different proof
method for Compactness eac …
18
votes
Accepted
Deep theorems and long proofs
There is a body of very interesting work surrounding the proof complexity of various formulations of the well-known pigeon-hole principle, the fact that there is no injective function from a set of si …
16
votes
When does $ZFC \vdash\ ' ZFC \vdash \varphi\ '$ imply $ZFC \vdash \varphi$?
With regard to your sub-question,
Now imagine a universe where $\text{Con}(\text{ZFC})$ holds but all the models of $\text{ZFC}$ are $\omega$-nonstandard and believe $\neg \text{Con}(\text{Z …
14
votes
What's a magical theorem in logic?
The Truth Lemma
The result says that what's true in a forcing extension $M[G]$ is just what's forced to be true by the path of the generic filter $G$. More precisely:
Suppose $M$ is a countable t …
14
votes
Accepted
Decidability of decidability
$\newcommand\Con{\text{Con}}
\newcommand\Dec{\text{Dec}}$
Let $F$ be the formal system in which the proofs are to be carried
out, when it comes to your formal assertions of the form
$\Dec(\varphi)$. …
14
votes
Accepted
Peano arithmetic vs. fast-growing hierarchy with pathological fundamental sequences
The answer is no. Choose a fundamental sequence for $\epsilon_0$ itself in the usual way, which I think is $\epsilon_0[n]=\omega^{\omega^{{\vdots}^\omega}}$, and then modify the earlier fundamental se …