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Questions about the branch of algebra that deals with groups.
14
votes
3
answers
1k
views
Does the Alternating group of degree $n>7$ have exactly one irreducible character of degree ...
We know that the alternating group of degree $n>7$ has an irreducible character of degree $n-1$. The latter number is the smallest nontrivial one for each the alternating group has an irreducible char …
13
votes
2
answers
810
views
Torsion-freeness of two groups with 2 generators and 3 relators and Kaplansky Zero Divisor C...
Let $G_1$ and $G_2$ be the groups with the following presentations:
$$G_1=\langle a,b \;|\; (ab)^2=a^{-1}ba^{-1}, (a^{-1}ba^{-1})^2=b^{-2}a, (ba^{-1})^2=a^{-2}b^2 \rangle,$$
$$G_2=\langle a,b \;|\; …
12
votes
Intersection of all normalizers
The intersection of all normalizers of subgroups of a group $G$ is called the norm of $G$. By a result of Schenkman [E. Schenkman, On the norm of a group, Illinois J. Math., 7 (1960) 150-152] the nor …
11
votes
Groups in which all characters are rational.
Sylow $2$-subgroups of the symmetric group $S_n$ of degree $n$ are rational.
There was a longstanding conjecture on rational groups saying that Sylow $2$-subgroups of a rational group are also ration …
10
votes
Automorphism fixes subgroups
It is called a power automorphism of the group $G$. The automorphism $g$ maps every element $x$ of $G$ to a power of $x$. See the following reference as a starting point.
Christopher D. H. Cooper, Po …
10
votes
A group-theoretic perspective on Frankl's union closed problem
If $G$ is a non-trivial finite group which can be generated by two non-trivial elements of prime power orders, then the answer to the question is affirmative. Let $\mathcal{G}$ be the set of all subgr …
10
votes
2
answers
433
views
Groups with no bounds on the size of abelian subgroups without infinite ones
Is there a group $G$ in which every abelian subgroup is finite and there is no upper bound on the sizes of its abelian subgroups?
Let me say that a counterpart of the question above has posed by Paul …
9
votes
3
answers
530
views
Nilpotency class of a certain finite 2-group
Let $G_d$ be the group with the following presentation
$$\langle x,y \mid x^{2^{d+1}}=1, x^4=y^2, [x,y,x]=x^{2^{d}}, [x,y,y]=1\rangle,$$
where $d>2$ is an integer.
It is clear that $G_d$ is a finite $ …
9
votes
1
answer
700
views
History of a conjecture/problem non-inner automorphisms of order p in finite p-groups
The following conjecture/problem posed in The Kourovka Notebook in 1973 by Ya. G. Berkovich:
Problem 4.13. Prove that every finite non-abelian $p$-group admits an automorphism of order $p$ which is …
9
votes
1
answer
2k
views
The line graphs of complete graphs and Cayley graphs
Let $n>3$ be an odd integer and let $K_n$ denote the complete graph on $n$ vertices.
For which integers $n$ the line graph $L(K_n)$ is a Cayley graph?
For even $n$, it follows from a result of Watkins …
8
votes
1
answer
556
views
The parity of the full automorphism group order of finite non-abelian groups of prime exponent
Is there a finite non-abelian group $G$ of prime exponent such that the full automorphism group of $G$ is of odd order?
7
votes
Realizing groups as commutator subgroups
Let me quote some well-known results and perhaps related problems which may be illuminating!
Let $G$ be a non-abelian finite $p$-group having cyclic center. Then, there is no finite $p$-group $H$ suc …
6
votes
2
answers
249
views
Zero divisors with support of size 3 in group algebras of finite groups
Are there a finite group $G$ and a field $\mathbb{F}$ such that $\gcd(3,|G|)=1$ and the group algebra $\mathbb{F}[G]$ contains a zero divisor whose support is of size $3$?
Recall that the support of …
6
votes
0
answers
219
views
Is always the ratio (number of commuting pairs of elements in a ring or a Lie algebra)/(the ...
(1) Is there a finite nilpotent ring $R$ such that the ratio
$$c(R)=\frac{|\{(x,y)\in R\times R \; | \; xy=yx\}}{|R|}$$
is not integer?
Edit 1: The nilpotent condition is put later.
Edit/Answer: A …
6
votes
1
answer
355
views
Zero divisors in complex group algebras of residually finite groups
Conjecture. There exists a function $f:\mathbb{N} \rightarrow \mathbb{N}$ such that if $\alpha$ and $\beta$ are non-zero elements of the complex group algebra $\mathbb{C}[G]$ of a finite group $G$ suc …