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Topological quantum field theory.
6
votes
1
answer
167
views
Commutative Frobenius algebra with non-invertible window element, but not square zero
For any commutative Frobenius algebra $A$ there is an associated window element $\omega \in A$. If $\mu: A \otimes A \to A$ denotes the multiplication, $1 \in A$ the unit, $b: A \otimes A \to k$ the n …
7
votes
Accepted
Are there 4d state sum models, extended TQFTs or chain mail invariant that detect smooth str...
This MO answer by Arun Debray gives an example in the unoriented case where two specific homeomorphic manifolds can be distinguished by a specific TFT of this kind.
In general all these constructions …
9
votes
Accepted
Are there examples of finite-dimensional complex non-semisimple non-commutative symmetric Fr...
Given any finite dimensional algebra $A$, consider the linear dual $\hat{A}= \hom(A, k)$ as an $A$-$A$-bimodule. Then $R = A \oplus \hat{A}$ may be equipped with an algebra structure as follows:
$$(a, …
17
votes
Accepted
How aggressive is the fibrant replacement of $\mathrm{Bord}_n$?
The completeness condition is not really about making things invertible which weren't already. It is about where the information about invertible morphisms is stored.
We can already see this with $(\i …
11
votes
1
answer
230
views
Are algebras with invertible linear duals always Frobenius?
Let $A$ be a finite dimensional algebra over a ground field $k$. The linear dual $A^* = Hom_k(A,k)$ is naturally an $A$-$A$ bimodule. I am interested in those algebras such that $A^*$ is an invertible …
4
votes
Accepted
An explicit expression for the naturality of the Serre automorphism in the bicategory of alg...
We will use the fact that $M$ is invertible. Let ${}_BN_A$ be an inverse to $M$. Thus we have isomorphisms
$${}_AM \otimes_B N_A \cong {}_AA_A$$
and
$${}_BN \otimes_A M_B \cong {}_BB_B$$
If we make th …
13
votes
1
answer
308
views
Does the Turaev-Viro theory for the generalized $E_6$ subfactor for $\mathbb{Z}/7$ distingui...
In the paper Sato-Wakui "COMPUTATIONS OF TURAEV-VIRO-OCNEANU INVARIANTS OF 3-MANIFOLDS FROM SUBFACTORS" they compute certain Turaev-Viro-Ocneanu invariants of certain lens spaces. One of the results i …
10
votes
2
answers
1k
views
Segal's 1999 Stanford lecture notes on TQFT, where to find them?
I am trying to track down a copy of Graeme Segal's 1999 lecture notes on topological field theory. These are sometimes referred to as the "Stanford lectures" or something similar.
For many years the …
12
votes
Accepted
How unique are extensions of TQFTs to lower dimension?
The question of which tqfts extend is a very interesting one. To make the question more mathematically precise, we can fix the target n-categories and ask for the tqfts to extend with respect to those …
11
votes
0
answers
412
views
When can we tell if PROPs, Algebraic Theories, etc. are faithfully detected in a given categ...
I am interested in understanding a certain phenomenon. I am hoping this sort of problem has been studied before, but I don't know the proper terminology and am having trouble finding answers. I am goi …
10
votes
Accepted
Homotopy Fixed Points of SO(2) on Fully Dualizable Algebras
I might be confused about your question. Are you asking...
How is trivializing the $O(n)$-action the same as giving an $O(n)$-equivariant non-degenerate trace? (as per Lurie's theorem 3.1.8).
How ca …
9
votes
Accepted
Spin TQFT's in dimensions (1+1)
This is covered in Moore and Segal "D-branes and K-theory in 2D topological field theory". In particular on around page 16 there is a characterization analogous to "1+1 TQFTs = Commutative Frobenius a …
15
votes
Accepted
Cohomology rings and 2D TQFTs
These 2D TQFTs do not come from extended theories (unless X is discrete). I interpret this as saying that these theories are non-local (in the 2D bordism) and so you will have trouble interpreting the …
13
votes
Why are fusion categories interesting?
I also wrote a sequence of blog posts explaining the Turaev-Viro construction from the point of view of planar algebras. It has pretty pictures and might be relevant.
TQFTs via Planar Algebras I
TQF …
8
votes
1
answer
446
views
Separable and finitely generated projective but not Frobenius?
Let R be a commutative ring, and $A$ an $R$-algebra (possibly non-commutative). Then $A$ is separable if it is finitely generated (f.g.) projective as an $(A \otimes_R A^{\mathrm{op}})$-algebra. Suppo …