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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
5
votes
Almost Complex Structures: 'Tame' versus 'Compatible'
To add to Sam's answer, compatible almost complex structures are often needed in applications of Gromov-Witten theory to Hofer geometry. Even more fundamentally they are necessary in the construction …
3
votes
0
answers
145
views
Growth of norm of curvature under direct sum or existence of universal connection
For a Hermitian vector bundle E over a Riemannian $(X,g)$ and a unitary connection A we may define the sup norm of the curvature by:
$$\|R_A\|=\sup \{\| tracefree (R_A (v))\|_{op} \mid v \in \Lambda ^ …
3
votes
1
answer
197
views
Does the group of compactly supported diffeomorphisms have the homotopy type of a CW complex?
It is known that the group of diffeomorphisms of a compact manifold with the natural $C^{\infty}$ topology has the homotopy type of a countable CW complex. See for instance this thread: Is the space o …
2
votes
2
answers
280
views
Mean curvature upper bounds and area, or geodesic curvature upper bounds and length
Let $M$ be a closed manifold with non-torsion $\pi_2$, and $A$ a non-trivial free homotopy class of a map $f: S^2 \to M$.
Let $S$ be the set of (immersed) class $A$ surfaces in $(M,g)$ with mean curva …
1
vote
1
answer
136
views
Examples of product negatively curved Riemannian manifolds
It is a well known theorem of Anderson that any vector bundle
over a negative sectional curvature Riemannian manifold
admits a metric of negative sectional curvature.
Q: Are there examples of complete …
0
votes
Accepted
Mean curvature upper bounds and area, or geodesic curvature upper bounds and length
The answer is No. Indeed it is no for spheres of all dimension assuming one can find an immersed class $A$ $S^n$ with mean curvature less than a given $C(A)$. The counterexamples can be generalized f …
0
votes
1
answer
97
views
Isometries of manifolds with non-positive sectional curvature
It is known since Bochner that for M compact with negative Ricci curvature, the group of isometries is discreet and hence finite. Are there any generalizations to compact non-positive sectional curvat …
0
votes
2
answers
337
views
Diameter of immersed surfaces with bounded from above mean curvature
Is the following true? I cannot see a counterexample and it seems very intuitively clear, at least in the embedded case.
Claim:
Consider the set $S$ of closed immersed Riemann surfaces $\Sigma \subse …
0
votes
0
answers
97
views
Deformed completion of negatively curved metric
Suppose X,g is a complete
negative sectional curvature Riemannian manifold. And $C \subset X$ is
compact submanifold.
What are the minimal conditions on $C$ so that
we can deform g on the restriction …