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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

5 votes
0 answers
330 views

On Galois' criterion for resolvents

Let $K$ be an algebraic number field, $f(x) = 0$ an algebraic equation over $K$ of degree $n \ge 2$ with only simple roots $x_1, \dotsc, x_n$, and $L \mathrel{:=} K[x_1, \dots, x_n]$ the splitting fie …
MathCrawler's user avatar
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2 votes
1 answer
431 views

Proof for an explicit formula for the even Euler numbers

The EULER numbers $E_n$, $n \in \mathbb{N}$, are defined via the TAYLOR expansion of the hyperbolic secant: \begin{equation} \text{sech}(x) = \sum_{n=0}^{\infty} \frac{E_n}{n!} x^n = \sum_{n=0 …
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1 vote

Proof for an explicit formula for the even Euler numbers

@Sam Hopkins: The formula there reads \begin{equation*} E_{2n}=\sum_{k=1}^{2n }(-1)^k\frac{1}{2^k}\sum_{\ell=0}^{2k}(-1)^{\ell}\binom{2k}{\ell}(k-\ell)^{2n} \end{equation*} which is slightly diffe …
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2 votes
1 answer
230 views

Proof of a binomial identity

Computations with Maple suggest the following binomial identity \begin{equation*} \forall{p,j}: \sum_{k=j+1}^{p+1} (-1)^j \dfrac{1}{k}\binom{k-1}{j} = \sum_{k=j+1}^{p+1} (-1)^{k-1} \dfrac{1} …
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2 votes

What are immediate applications of the classification of connected reductive groups?

Come that far, one can begin to exploit the subgroups, turn one's attention to symmetric spaces, of which there are the compact and noncompact ones, the riemannian and the hermitian ones. And one can …
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