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1 vote

Constant Gaussian curvature disks

The answer is yes. Since curvature is 1, there is an isometric immersion $\iota\colon D\looparrowright \mathbb{S}^2$. Note that the curve $\iota(\partial D)$ has constant curvature, therefore $\iota(\ …
Anton Petrunin's user avatar
3 votes

How to correctly state Cauchy's rigidity theorem?

Yes, formally speaking the statement is incorrect. The correct assumption is: there is a continuous bijection between the surfaces of two polyhedra that maps each facet to a facet by isometry. Alexand …
Anton Petrunin's user avatar