For a fixed $u \in BV(\mathbb{R}^N)$, consider the function $h:(0,+\infty) \to BV(\mathbb{R}^N)$, given by
$h(t) = u (tx)$.
Does $h$ is continuous?
For a fixed $u \in BV(\mathbb{R}^N)$, consider the function $h:(0,+\infty) \to BV(\mathbb{R}^N)$, given by
$h(t) = u (tx)$.
Does $h$ is continuous?