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18 votes
1 answer
783 views

Are there any "simple" monoids with intermediate growth?

The discovery of the Grigorchuk group which has intermediate growth caused a number of other such groups to be found, but they are all fairly complicated, and as far as I know none of them are ...
saolof's user avatar
  • 1,947
7 votes
0 answers
260 views

Generating the monoid of injective endomorphisms of the free group

Let $F$ be the free group of rank $2$ (or any finite rank if this does not matter). The set of injective group endomorphisms $F\to F$ forms a monoid $M$ by compositions. Is there a simple looking set ...
Lvzhou Chen's user avatar
6 votes
0 answers
183 views

Examples of groups with a positive homogeneous presentation without the Haagerup property or not of type $F_\infty$

I am looking for groups with a certain presentation that do not have the Haagerup property or are finitely presented but not of type $F_\infty$ (meaninig that for some $n\geq 3$ we cannot find any ...
Arnaud's user avatar
  • 61
6 votes
0 answers
572 views

Computing the pro-solvable closure of a finitely generated subgroup of a free group

The pro-solvable topology on a group $G$ is the unique group topology such that the set of normal subgroups $N\lhd G$ with $G/N$ a finite solvable group is a fundamental system of neighborhoods of the ...
Benjamin Steinberg's user avatar
5 votes
1 answer
498 views

Percolation in Cayley graphs of semigroups.

Percolation in Cayley graphs of groups are studied by many researchers. There are also the concept Cayley graphs for semigroups. Are there any research about percolation in Cayley graphs for ...
Jianrong Li's user avatar
  • 6,201
4 votes
0 answers
72 views

When is the submonoid preserving a subspace finitely generated?

Let $T$ be a topological space with at least one open set whose closure is not open. Let $G$ be a finitely generated group acting by homeomorphisms on $T$. Let $S\subset T$ be a subspace. Under what ...
Nassim's user avatar
  • 51
3 votes
1 answer
125 views

Quasi-isometries and E-unitary inverse semigroups

Let $S = \langle K\rangle$ be a finitely generated inverse semigroup, where $K \subset S$ is a fixed, finite and symmetric set of generators. Preliminaries: Recall that we say that $s, t \in S$ are $\...
Diego Martinez's user avatar
1 vote
0 answers
70 views

Another matrices for a semigroup with intermediate growth

Nathanson showed that the Okninski's semigroup $S$ of $2×2$ matrices which is generated by the set $H=\{A,B\}$, where $ A=\begin{bmatrix} 1&1\\ 0&1\\ \end{bmatrix} , B=\begin{bmatrix} 1&0\\...
mahdi meisami's user avatar