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8 votes
2 answers
626 views

An inverse to functional calculus

Given a Borel function f:RR{}, functional calculus allows to calculate F(x) for any unbounded selfadjoint operator x on a Hilbert space H, ...
rpk's user avatar
  • 176
6 votes
1 answer
1k views

Unbounded version of continuous functional calculus

For a normal operator T on a Hilbert space H, it is well known that for any continuous complex valued function f on the spectrum of T, we have a well-defined operator $f(T) \in B({\cal ...
Dave Shulman's user avatar