Skip to main content

All Questions

Filter by
Sorted by
Tagged with
15 votes
2 answers
2k views

Solvability in differential Galois theory

It is well known that the function $f(x) = e^{-x^2}$ has no elementary anti-derivative. The proof I know goes as follows: Let $F = \mathbb{C}(X)$. Let $F \subseteq E$ be the Picard-Vessiot extension ...
the L's user avatar
  • 1,214