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13 votes
1 answer
2k views

Are some interesting mathematical statements minimal?

Gödel's set $\mathrm{L}$, of constructible sets, decides many interesting mathematical statements, as the Continuum hypothesis and the Axiom of Choice. Are some interesting mathematical questions, ...
Frode Alfson Bjørdal's user avatar
10 votes
2 answers
737 views

Constructible models of New Foundations?

Hi all! Is there anything like Gödel's constructible universe for New Foundations? More precisely, I would like a process for taking a model $M$ of NF, and using it to build a model $L \subseteq M$ ...
Nick Thomas's user avatar
9 votes
2 answers
426 views

Can local $0^\#$ exists in L?

Assume $0^\#$ exists and there is an inaccessible cardinal. Are there two transitive sets $M,N$ s.t. $M\in N,M\vDash ZF+V=L[0^\#],N\vDash ZF+V=L$?
Reflecting_Ordinal's user avatar
8 votes
3 answers
538 views

Elementary countable submodels in Gödel's universe

By the downward Lowenheim-Skölem theorem we can find two countable ordinals $\alpha < \beta$ such that $L_\alpha \prec L_{\omega_1}$ and $L_\beta \prec L_{\omega_1}$. That is, $L_\alpha$ and $L_\...
Johan's user avatar
  • 531
8 votes
1 answer
627 views

Is $\mathsf{ZFC+V=L}$ consistently $\omega$-complete?

This was previously asked and bountied on MSE: For brevity, let $T$ be $\mathsf{ZFC+V=L}$. Say that an extension of $\mathsf{ZFC}$ is $\omega$-complete iff it has exactly one $\omega$-model up to ...
Noah Schweber's user avatar
7 votes
2 answers
518 views

Can countable ordinals start gaps of every order in the constructible universe?

Define "$\alpha$ starts a gap of order $n+1$ and length $\beta$" iff $\mathcal P^n(\omega)\cap (L_{\alpha+\beta}\setminus L_\alpha)=\emptyset\land\forall\gamma\in\alpha: L_\alpha\setminus L_\...
Boris Dimitrov's user avatar
6 votes
1 answer
571 views

Parameter-free effective cardinals

In the paper "Effective cardinals and determinacy in third order arithmetic" by Juan Aguilera, effective cardinals is defined. I'm curious about its little variation, parameter-free ...
Reflecting_Ordinal's user avatar
5 votes
1 answer
407 views

Height of diamond

Assume $V=L$. Let $\alpha$ be the least ordinal such that there is a $\Diamond_{\omega_1}$-sequence in $L_\alpha$. It's obvious that $\omega_1 < \alpha < \omega_2$. Do we have some better ...
Reflecting_Ordinal's user avatar
3 votes
1 answer
325 views

If we have a class like $L$ but allowing a set number of unbounded quantifiers, is it strict superset of $L$?

The definition of $L$ only permits bounded quantifiers. If we allow a certain number of unbounded quantifiers, does this result in a strict superset of $L$? For example: $$ \operatorname{Def}^{\...
Christopher King's user avatar
2 votes
1 answer
243 views

Is stable ordinals in non-well-founded model the same as well founded models?

Let $BST$ be the axiom system $KP$ - $\Delta_0$ collection. For an ordinal $\alpha$, we say that $\alpha$ is $\varphi$-$\Sigma_n$-stable, if there is a $\beta>\alpha$ satisfies the formula $φ$ such ...
Reflecting_Ordinal's user avatar
2 votes
0 answers
240 views

When is a $\Sigma_n$ Skolem hull a proper submodel?

For $M$ an amenable structure and $X \subset M$, the $\Sigma_n$ Skolem hull of $X$ is a $\Sigma_n$-elementary submodel of $M$. That is, as presentend in Devlin, Constructibility, pp. 85-88, for $h_n$ ...
Johan's user avatar
  • 531
1 vote
1 answer
228 views

Is there a 'Constructible Universe' that is a submodel of a non-transitive model of $ZF$?

In Barwise's book, Admissible Sets and Structures, the following statement is made (on pg. 8): "...if $ZF$ is consistent, so is $ZF$ + "There is no transitive model of $ZF$" He mentions this fact ...
Thomas Benjamin's user avatar
1 vote
1 answer
249 views

Recursively inaccessible ordinals and non locally countable ordinals

This answer seems to imply that: for an ordinal $\alpha$, to be recursively inaccessible (i.e. $\alpha$ is admissible and limit of admissible) implies to be not locally countable (i.e. $L_\alpha \...
Johan's user avatar
  • 531