All Questions
9 questions
9
votes
1
answer
1k
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A strange property about modulus
I came across this strange property :
...
4
votes
1
answer
207
views
Nearly De Bruijn sequences constructed from De Bruijn sequences
Let $w$ be a De Bruijn $01$-sequence of the type $B(2,n)$; i.e., a cyclic $01$-sequence that contains every $n$-digit $01$-sequence exactly once. Let $x$ be a $01$-sequence of length $n$. When and ...
5
votes
1
answer
264
views
Hamming distance between $a+b$ and $a \oplus b \oplus ((a \land b) \ll 1)$
Motivation. In their paper about the cryptographic scheme NORX, the authors use a fast approximation of + by bitwise operations (taking fewer CPU cycles than proper addition) using the formula $$a+b "=...
5
votes
1
answer
275
views
How to generate $n$ FP32 rationals s.t. no two distinct k-el. subsets have same sum?
First some
Background: I have lots and lots of integer matrices, whose rows are $k$-combinations (without repetitions and sorted) of numbers from the set $S:=\{1,...,n\}$ and needed to be compared ...
0
votes
3
answers
1k
views
Given $N$ integers on a circle, how to choose them in pairs to obtain minimum sum?
(Added by YCor 2019 July 7): it has been mentioned in the comments that this is part of a contest "Circular merging, July Challenge 2019 Division 1", where an equivalent question (just more clearly ...
9
votes
0
answers
2k
views
Exactly Counting the Number of Lattice Points in an $n$-Dimensional Sphere
Let $S_n(R)$ denote the number of lattice points in an $n$-dimensional "sphere" with radius $R$. For clarification, I am interested in lattice points found both strictly inside the sphere, and on its ...
5
votes
2
answers
500
views
How to construct particular De Bruijn sequences
For $n \ge 2$, there is at least one binary DeBruijn sequence beginning with $n$ zeros followed by $n$ ones. Is there a straightforward way to construct such a sequence for each $n \ge 2$? Examples:
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6
votes
1
answer
352
views
Number of partitions whose blocks form arithmetic progressions
As is known, the set $\{1,\ldots,n\}$ has $2^n$ many subsets and $B_n$ (the $n$th Bell number) many partitions, where clearly $B_n<2^{2^n}$ and it is actually known that $B_n<n^n$ for large $n$. ...
3
votes
1
answer
296
views
Question about the elementary divisors of a special matrix
I have the following question:
Is there a closed formula for the elementary divisors of the Matrix
$M=\lbrace (m_{ij})\rbrace_{i=1,...,n,\ j=1,...,k}$, where $m_{ij}$ is the greatest common ...