Suppose that $(X,\Sigma,\mu)$ is a measured set with respect to $\sigma$algebra $\Sigma$. Suppose that $L^\infty(X,\mu)$ is the set of all $\mu$equal bounded $\Sigma$measurable functions on $X$. Indeed equally, one may say that $L^\infty(X,\mu)$ is the dual of $L^1(X,\mu)$. What is the spectrum of $(L^\infty(X,\mu),\\cdot\_\infty)$ as a Banach (C^*) algebra? Thank you very much.

2$\begingroup$ It doesn't directly affect your question, but I have a feeling that $L^\infty$ is only the dual of $L^1$ under certain mild conditions on your space and your sigmaalgebra. $\endgroup$ – Yemon Choi Jun 8 '12 at 6:45

1$\begingroup$ Why the vote to close? $\endgroup$ – Johannes Ebert Jun 8 '12 at 7:56

1$\begingroup$ I've had a rough night, and might be missing something, but are you looking for the topological space which would be the Gelfand spectrum of the abelian $C*$algebra $L^\infty$? If that's the case you should look for completely discontinuous spaces on Google, or have a look at KadisonRingrose, the part on VonNeumann algebras. $\endgroup$ – Amin Jun 8 '12 at 8:26

2$\begingroup$ Yes, a hyperstonean space will be the spectrum. For example, if $X=\mathbb Z$ with the counting measure, then the spectrum is $\beta Z$ (the StoneCech compactification). $\endgroup$ – Yulia Kuznetsova Jun 8 '12 at 8:31

2$\begingroup$ @Matthew: It's not a "standard fact"... it's a mathematical object. The OP is simply asking for extra information/intuition about that mathematical object. $\endgroup$ – André Henriques Jun 8 '12 at 11:33
Here is a description of the spectrum of $L^\infty([0,1];\mu)$ for an arbitrary Borel measure $\mu$ on $[0,1]$.
Consider the following poset, which I call $P$ :
• The objects of $P$ are decompositions $\mathbf X=\{X_1,\ldots, X_n\}$ of $[0,1]$ into finitely many $\mu$measurable sets $[0,1]=X_1\cup X_2\cup\ldots\cup X_n$, $X_i\cap X_j=\emptyset$. Two decompositions $\mathbf X$ and $\mathbf Y$ are declared equal is there exists a permutation $\sigma$ such that $X_i=Y_{\sigma(i)}$ up to a $\mu$measure zero set.
• The partial order on $P$ is given by refinement: $\mathbf X \prec \mathbf Y$ if
$Y_1=X_1\cup\ldots \cup X_{n_1}$, $Y_2=X_{n_1+1}\cup\ldots \cup X_{n_2}$, $\ldots$ (up to permutation and $\mu$measure zero sets)
Note that the poset $P$ is filtered: given a finite set $\mathbf X_1, \mathbf X_2, \ldots, \mathbf X_n$ of elements of $P$, there is always a common refinement, i.e., an element $\mathbf X\in P$ such that $\mathbf X\prec \mathbf X_i\\,\forall i$
Given a $\mu$measurable subset $X\subset [0,1]$, let me denote by $X_ \mu \subset [0,1]$ the $\mu$adherence of $X$: $$ X_ \mu:=\{x\in [0,1]: \forall \varepsilon>0\quad \mu(X\cap B_{x,\varepsilon})>0\}, $$ where $B_{x,\varepsilon}$ denotes the ball of radius $\varepsilon$ around the point $x$. Given $\mathbf X=\{X_1,\ldots,X_n\} \in P$, we also write $\mathbf X_ \mu$ for the disjoint union $$\mathbf X_ \mu:=X_1_ \mu\sqcup\ldots\sqcupX_n_ \mu.$$
Note that if $\mathbf X \prec \mathbf Y$, then there is a natural projection map $\mathbf X_ \mu \twoheadrightarrow \mathbf Y_ \mu$.
Given the above preliminaries, the spectrum of $L^\infty([0,1];\mu)$ is given by the inverse limit of the functor $P\to Top, \mathbf X\mapsto \mathbf X_ \mu$:
$$Spec\big(L^\infty([0,1];\mu)\big) =\quad \underset{\mathbf X\in P}{\underset\leftarrow\lim} \mathbf X_ \mu$$

2$\begingroup$ Why is this true? What is the homeomorphism between the two spaces? $\endgroup$ – Jonathan Gleason Jan 5 '17 at 12:44
I'm recording here some references on the object $\tilde X = \mathrm{Spec}(L^\infty(X,\Sigma,\mu))$ (many of which were communicated to me recently by Balint Farkas), assuming for sake of simplicity that $\mu$ is a probability measure to avoid some technicalities. As the references below show, this object has been discovered and used multiple times in the literature, but lacks a standardised name.
The earliest reference I know of that uses this space is
Halmos, Paul R., On a theorem of Dieudonne, Proc. Natl. Acad. Sci. USA 35, 3842 (1949). ZBL0031.40701.
who calls it the "Kakutani space" of $X$. Another early reference (referring to $\tilde X$ as a "perfect measure space") is
Segal, I. E., Equivalences of measure spaces, Am. J. Math. 73, 275313 (1951). ZBL0042.35502.
and the space is referred to as the "Gelfand space" of $X$ and used to relate ergodic theory with topological dynamics in
Ellis, Robert, Topological dynamics and ergodic theory, Ergodic Theory Dyn. Syst. 7, 2547 (1987). ZBL0592.28015.
An equivalent construction of the space (based on the LoomisSikorski theorem) also appears in
Doob, Joseph L., A ratio operator limit theorem, Z. Wahrscheinlichkeitstheor. Verw. Geb. 1, 288294 (1963). ZBL0122.36302.
and implicitly in
Fremlin, D. H., Measure theory. Vol. 3. Measure algebras, Colchester: Torres Fremlin (ISBN 0953812936/pbk). 693 p., 13 p. (2004). ZBL1165.28002.
The space is also discussed in Chapter 12 of the recent text
Eisner, Tanja; Farkas, Bálint; Haase, Markus; Nagel, Rainer, Operator theoretic aspects of ergodic theory, Graduate Texts in Mathematics 272. Cham: Springer (ISBN 9783319168975/hbk; 9783319168982/ebook). xviii, 628 p. (2015). ZBL1353.37002.
(who call it the "Stone model" of $X$) and in a recent preprint of Jamneshan and myself we refer to it as the "canonical model" and rely on it to perform various producttype constructions on abstract measurepreserving systems. As we note in that paper, it behaves in many ways like the StoneCech compactification of locally compact Hausdorff spaces.
Some key properties of this space (discussed for instance in my paper with Jamneshan):
$\tilde X$ is a Stonean space (compact Hausdorff and extremally disconnected). In particular, by a result of Gleason, it is projective in the category of compact Hausdorff spaces: given any surjective continuous map $\pi: Y \to Z$ on compact Hausdorff spaces, any continuous map from $\tilde X$ to $Z$ can be continuously lifted to $Y$. One can also identify $\tilde X$ with the Stone space of the probability algebra of $X$ (the measurable sets modulo the null sets). In particular, by the LoomisSikorski theorem, the probability algebra of $X$ is isomorphic to the Baire sets of $\tilde X$ modulo the meager sets.
The map $X \mapsto \tilde X$ can be viewed as a covariant functor from the category of probability spaces (or an abstraction of this category which we call the category of opposite probability algebras) to the category of compact Hausdorff probability spaces. In fact it is leftadjoint to the forgetful functor from compact Hausdorff probability spaces to opposite probability algebras (much as the StoneCech compactification is leftadjoint to the forgetful functor from compact Hausdorff spaces to locally compact Hausdorff spaces). Related to this, $\tilde X$ is "universal" amongst all compact Hausdorff spaces whose probability algebra is isomorphic to that of $X$, in the same way that the StoneCech compactification is universal amongst all compactifications of a locally compact Hausdorff space.
There is a natural lift $\tilde \mu$ of $\mu$ to $\tilde X$, using the Baire $\sigma$algebra on $\tilde X$. A Baire set in $\tilde X$ is $\tilde \mu$null if and only if it is meager. If $X$ is itself a compact Hausdorff space (with the Baire $\sigma$algebra), then $\mu$ is Radon and there is a continuous probabilitypreserving map from $\tilde X$ to $X$, whose image is the support of $\mu$.
One has an isomorphism $C(\tilde X) = L^\infty(\tilde X)$. Thus $\tilde X$ enjoys a strong version of Lusin's theorem that we refer to as the "strong Lusin property": every bounded Bairemeasurable function on $\tilde X$ is equal outside of a null set (or equivalently, a meager set) to a unique continuous function. Similarly, any Bairemeasurable map from $X$ to a compact Hausdorff space $K$ can be uniquely identified with a continuous map from $\tilde X$ to $K$.

1$\begingroup$ The StoneCech compactification (of $\mathbb N$, let's say) can also be viewed as the spectrum of (the Banach algebra) $\ell^{\infty}$, so the analogies are not entirely coincidental perhaps. $\endgroup$ – Christian Remling Oct 25 '20 at 18:46

1$\begingroup$ Yes, the StoneCech compactification of an LCH $X$ is the Gelfand spectrum of the space $C_b(X)$ of bounded continuous functions, whereas the canonical model of a probability space $X$ is the Gelfand spectrum of the space $L^\infty(X)$ of bounded measurable functions, which further reinforces the analogy. $\endgroup$ – Terry Tao Oct 25 '20 at 18:48

4$\begingroup$ A small remark on the first property in your list: for compact Hausdorff spaces $K$, being hyperstonian is not actually the same as being extremally disconnected (extremally disconnected spaces are sometimes called "Stonian", which is slightly weaker than hyperstonian). More precisely, $K$ is Stonian iff $C(K)$ is Dedekind complete with respect to the pointwise order, while $K$ is hyperstonian iff $C(K)$ has a predual Banach space. $\endgroup$ – Jochen Glueck Oct 25 '20 at 21:06

1$\begingroup$ Oops, thanks for pointing that out, the terminology is now corrected. $\endgroup$ – Terry Tao Oct 25 '20 at 21:16