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Timeline for Spectrum of $L^\infty(X,\mu)$

Current License: CC BY-SA 3.0

12 events
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Oct 25, 2020 at 18:40 answer added Terry Tao timeline score: 14
Jun 8, 2012 at 19:27 vote accept unknown is my last name
Jun 8, 2012 at 15:47 comment added Matthew Daws A related question on math.se: math.stackexchange.com/questions/81324/…
Jun 8, 2012 at 11:58 comment added Matthew Daws @André: Okay, we agree to disagree I guess. +1 your answer.
Jun 8, 2012 at 11:33 comment added André Henriques @Matthew: It's not a "standard fact"... it's a mathematical object. The OP is simply asking for extra information/intuition about that mathematical object.
Jun 8, 2012 at 11:30 answer added André Henriques timeline score: 12
Jun 8, 2012 at 8:41 comment added Matthew Daws Unless I'm missing something, this is a very standard fact about abelian von Neumann algebras which can be found in standard texts, just as Amin and Yulia say. So voting to close, as not research level.
Jun 8, 2012 at 8:31 comment added Yulia Kuznetsova Yes, a hyperstonean space will be the spectrum. For example, if $X=\mathbb Z$ with the counting measure, then the spectrum is $\beta Z$ (the Stone-Cech compactification).
Jun 8, 2012 at 8:26 comment added Amin I've had a rough night, and might be missing something, but are you looking for the topological space which would be the Gelfand spectrum of the abelian $C*-$algebra $L^\infty$? If that's the case you should look for completely discontinuous spaces on Google, or have a look at Kadison-Ringrose, the part on VonNeumann algebras.
Jun 8, 2012 at 7:56 comment added Johannes Ebert Why the vote to close?
Jun 8, 2012 at 6:45 comment added Yemon Choi It doesn't directly affect your question, but I have a feeling that $L^\infty$ is only the dual of $L^1$ under certain mild conditions on your space and your sigma-algebra.
Jun 8, 2012 at 5:43 history asked unknown is my last name CC BY-SA 3.0