I have a very basic question on Lie algebras. I'm doing particle physics, and a lot of emphasis seems to be placed on the weight diagrams of simple Lie algebras. But these simple Lie algebras are all that ever seems to be discussed. Can anyone tell me in intuitive terms how the weight diagrams of semi-simple Lie algebras relate to those of the simple Lie algebras that sum to make the semi-simple algebras? Does one somehow 'add' the weight spaces together? (Sorry if this sounds really stoopid!)
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2$\begingroup$ I think the answer is yes: take the direct sum of the vector spaces in which the root systems of the simple pieces live. $\endgroup$– Yemon ChoiCommented Mar 24, 2012 at 20:50
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$\begingroup$ As Allen suggests, this question is perhaps more suitable for stackexchange. Aside from that, a tag "lie-algebras" is needed, since "algebra" is much too broad. $\endgroup$– Jim HumphreysCommented Mar 25, 2012 at 14:41
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I think this is more stackexchange-worthy, but here goes.
I'm a little afraid you're mixing up general weight diagrams with the root system, which is the weight diagram of the adjoint representation. The root system of $G\times H$ lives in a space that's just the Cartesian product of the two individual spaces, and is the disjoint union: $$ \Delta_{G\times H} = (\Delta_G \times 0) \cup (0 \times \Delta_H). $$
If one's talking about weight diagrams of irreducible representations of $G\times H$ (which the adjoint representation is not), it helps to know that they're all of the form $V\otimes W$. So then, one takes the convolution of the two weight multiplicity diagrams, again inside that Cartesian product:
$$ mult(V\otimes W)_{\lambda,\mu} = mult(V)_\lambda \ mult(W)_\mu. $$
answered Mar 24, 2012 at 23:25