Let $G$ be a one-relator group $\langle A \mid R = 1 \rangle$. Then clearly $G$ is finite if and only if it is cyclic of finite order, i.e. can be given by a presentation $\langle a \mid a^n = 1 \rangle$ for some $n > 0$.
1. What are the finite two-relator groups?
This question might be unanswerable. An indication of why this problem might be difficult comes from a classical example due to Dehn. He shows that for any $n \in \mathbb{N}$ and $m \in \{ 2, 3, 4, 5\}$, the group $$ G_{m,n} = \langle a,b \mid a^2 = b^3, \: (ab)^m b^{3n} = 1 \rangle $$ is finite, i.e. a quotient of the trefoil knot group. Indeed, he shows that these groups fit in short exact sequences $$ 1 \longrightarrow C_k \longrightarrow G_{m,n} \longrightarrow H_m \longrightarrow 1 $$ where $k \in \{ 3n + 5, 4n + 10, 6n + 20, 12n + 50 \}$ and $H_m \in \{ S_3, A_4, S_4, A_5 \}$ depending on the value of $m$ (indexed as above). Thus the question is already quite non-trivial even when one of the relators is rather simple. A partial and valuable answer to Question 1 would hence be an answer to the following question:
2. What are the finite (relative) one-relator quotients of the trefoil knot group $\langle a, b \mid a^2 = b^3 \rangle$?
In particular, is $G_{m,n}$ finite for any $m>5$ and $n > 0$? (I suspect not). Any thoughts would be welcome!