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Have You seen these result as follows before?

  • In Figure 1: $AA'=BB'=tAB$; $CC'=DD'=tCD$, where t is real number then $ABCD$ is a cyclic quadrilateral iff $A'B'C'D'$ is a cyclic quadrilateral.

  • In the Figure 2: $B_a, C_a, C_b, A_b, A_c, B_c$ lie on a conic.

See also:

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  • $\begingroup$ Power of a point might be used to prove it. $\endgroup$ Commented Aug 12 at 1:35
  • $\begingroup$ Yes, proof is easy $\endgroup$ Commented Aug 12 at 1:58

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