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Suppose time-oriented spacetimes $(M_1 , g_1)$ and $(M_2, g_2)$ are homeomorphic under their manifold topologies $\mathcal{M}_1$ and $\mathcal{M}_2$ respectively.

Let's call this map $\phi: (M_1, \mathcal{M}_1) \rightarrow (M_2, \mathcal{M}_2)$.

The Lorentzian metrics $g_1$ and $g_2$ induce binary relations $\ll_1$ and $\ll_2$ over their manifolds respectively which is defined as such:

$p \ll q \leftrightarrow$ there exists a time-like path connecting $p$ to $q$

Suppose the homeomorphism $\phi$ is an $\ll$ isomorphism, meaning:

$$\forall p,q \in M_1 : p \ll_1 q \leftrightarrow \phi(p) \ll_2 \phi(q) $$

The path topology on a Lorentzian manifold is defined as such:

The finest topology over $M$ such that its open sets induce the same topology on each of the timelike curves in $M$(subspace topology), as the manifold topology does.

The question is if $\phi$ as a $\ll$-isomorphism and manifold topology homeomorphism, imply path topology homeomorphism(even if not under exactly the same map though this is less appreciated but still valuable).

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    $\begingroup$ Downvote/upvote without comment = irresponsible $\endgroup$ Commented May 17 at 12:02
  • $\begingroup$ You have not said what a "spacetime" is. From your language I would assume it means a time-oriented Lorentz manifold. Also, what is the induced topology on the set of timelike curves -- are you using the compact-open topology? $\endgroup$ Commented May 17 at 21:42
  • $\begingroup$ Spacetime is surely time-orientable. The finest topology over M such that its open sets induce the same topology on each of the timelike curves in $M$, as the manifold topology does. @RyanBudney $\endgroup$ Commented May 17 at 22:06
  • $\begingroup$ You would get more engagement if you define the terms you use. Not certain if you have answered my latter question. So are you talking about putting a topology on the set of timelike curves, or are you talking about restricting the topology of $M$ to individual timeline curves, i.e. subspace topology? $\endgroup$ Commented May 17 at 22:11
  • $\begingroup$ I mean the later @RyanBudney ok I do my best to learn talking in a mathematician friendly way. But I do not guarantee that there's faintest importance in these questions I pose here. $\endgroup$ Commented May 17 at 22:20

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