I asked this question at StackExchange, but got no answer. So I am reposting it here.
I eventually want to check how the Hopf fibration $$ S^{2n+1}\to {\mathbb C}P^n $$ satisfies the Riemannian submersion formula, but I am frustrated that I could not even see how things work for $S^{2n+1}$ alone.
I can take either of the models $$ S^{2n+1} = U(n+1)/U(n) = SU(n+1)/SU(n+1), $$ but maybe the first is easier.
Then $G=U(n+1), H=U(n), {\mathfrak g}={\mathfrak u}(n+1), {\mathfrak h}={\mathfrak u}(n)$, diagonally embedded in ${\mathfrak u}(n+1)$ with the last entry 0. Let the invariant metric be $$ \langle A, B\rangle = -\frac{1}{2} \operatorname{Re Tr }AB = \frac{1}{2} \operatorname{Re Tr} AB^*.$$ Let $${\mathfrak m} = {\mathfrak h}^\perp, $$ whose dimension is $2n+1$. I am supposed to check that for any orthonormal $X, Y\in {\mathfrak m}$, the sectional curvature $$ K(X, Y) = 1. $$
Note that for the ${\mathbb C}P^n=SU(n+1)/U(n)$ case, the $K$ ranges from 1 to 4, and I can see that in this calculation, depending on if $X$ and $Y$ are in a complex subspace.
Then I don't see how it works out in the $S^{2n+1}$ case, as we should always have $K$ as a constant 1. I undestand that in this case, $[{\mathfrak m}, {\mathfrak m}]\not\subset {\mathfrak h}$, so I need to use the more general formula (Cheeger & Ebin, Cor. 3.33) $$ K(X, Y) = \frac{1}{4} \|[X, Y]_{\mathfrak m}\|^2 + \|[X, Y]_{\mathfrak h}\|^2, $$ but it still would not work for me.
If $X, Y$ are in a complex subspace, say \begin{align} X&=E_{1, n+1}-E_{n+1, 1}, \\ Y&=i(E_{1, n+1}+E_{n+1, 1}), \text{ then}\\ [X, Y] &= 2iE_{1, 1} - 2iE_{n+1,n+1}. \end{align} I would get $2\frac{1}{2}$ as my answer.
I know I may be too obsessed, and this could be a normalization issue, but your help would be appreciated.