A long comment: the derivative is not positive for all $x$, $n$. Thus there is the need for some more sophisticated argument than monotonicity.
The derivative is $$ - \Im \left( e^{ix}\cdot \frac{e^{inx} -1}{e^{ix}-1} \right).$$
The derivative being positive corresponds to $$\textrm{arg}\left( e^{ix}\cdot \frac{e^{inx} -1}{e^{ix}-1} \right) \le 0 .$$
Using additivity of arg, this reformulates as $$ \textrm{arg}(e^{ix}) -\textrm{arg}(e^{ix} -1 ) + \textrm{arg}(e^{inx} -1) \pmod{2 \pi} \in [0, \pi] .$$ Note that $y\equiv nx \pmod{2 \pi} $ can be almost anything if $x$ is irrational, thus in particular we would have $$ \textrm{arg}(e^{ix}) -\textrm{arg}(e^{ix} -1 ) + \textrm{arg}(e^{iy} -1) \pmod{2 \pi} \in [0, \pi] .$$ The $y$-term ranges over $[3\pi/4, 5\pi/4]$, thus we should have $$\textrm{arg}(e^{ix}) -\textrm{arg}(e^{ix} -1 ) \in [5/4\pi, 7/4\pi].$$
If $x$ is very small and positive, the expression is close to $3/4 \pi$, thus it is false.